Question

我是正则表达式和ruby的新手。下面是我开始使用

的例子

words= "apple[12345]: {123123}  boy 1233 6F74 2AC 28458 1594 6532 1500 D242g
apple[13123]: {123123123} girl Aui817E 9AD453 91321SDF 3423FS 1213FDAS 110FADA4 43ADAC0 1AADS4D8 BASAA24 "

我想在数组中提取boy 1233 6F74 .. to .. D242g 同样，我想在数组中提取girl Aui817E 9AD453 .. to .. 43ADAC0 1AADS4D8 BASAA24

我确实尝试过这样做不行。有人可以帮我这个简单的练习。提前致谢。

begin
     pattern = /apple\[\d+\]: \{\d+\} (\w) (\d+) (\d+) /
      f = pattern.match(words)
      puts " #{f}"
end

Answer 1

words.scan(/apple\[\d+\]: \{\d+\}(.+)/).map{|a| a.first.scan(/\S+/)}

或

words.each_line.map{|s| s.split.drop(2)}

输出：

[
  ["boy", "1233", "6F74", "2AC", "28458", "1594", "6532", "1500", "D242g"],
  ["girl", "Aui817E", "9AD453", "91321SDF", "3423FS", "1213FDAS", "110FADA4", "43ADAC0", "1AADS4D8", "BASAA24"]
]

Answer 2

array = words.scan(/apple\[\d+\]: {\d+}(.+)/).flatten.map { |line| line.scan(/\w+/) }

（{和}不需要在正则表达式中转义。）

返回

[
  ["boy", "1233", "6F74", "2AC", "28458", "1594", "6532", "1500", "D242g"],
  ["girl", "Aui817E", "9AD453", "91321SDF", "3423FS", "1213FDAS", "110FADA4", "43ADAC0", "1AADS4D8", "BASAA24"]
]

array[0]以＆＃34; boy＆＃34;开头给出一个数组，array[1]给出一个以＆＃34; girl＆＃34;开头的数组。

如何在ruby中使用正则表达式提取数字

2 个答案: