我使用wamp在我的本地计算机上使用php运行Apache。我确定dll文件在php.ini中取消注释(在apache和php bin文件夹下)。我有以下功能,每当我调用时,我都会收到错误:
卷曲失败,错误7无法连接到127.0.0.1端口8000:连接被拒绝
功能是:
function post($data) {
try{
$postUrl = "127.0.0.1:8000";
$ch = curl_init();
curl_setopt($ch,CURLOPT_URL,$postUrl);
curl_setopt($ch,CURLOPT_POST,TRUE);
curl_setopt($ch,CURLOPT_POSTFIELDS,$data);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
$x = curl_exec($ch);
if (FALSE === $x)
throw new Exception(curl_error($ch), curl_errno($ch));
curl_close($ch);
} catch (Exception $e){
$x = 'Curl failed with error ' . $e->getCode().' '.$e->getMessage();
}
return $x;
}
我已经通过SOF对此进行了研究,但无济于事。
答案 0 :(得分:0)
您可能指定了错误的端口。 Apache监听的默认端口是端口80(如果我没记错的话,对于wampserver的Apache实现也是如此)。试试这个:
function post($data) {
try {
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, '127.0.0.1:80');
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
$response = curl_exec($ch);
if ($response === false) throw new Exception(curl_error($ch), curl_errno($ch));
curl_close($ch);
} catch (Exception $e) {
$response = 'Curl failed with error ' . $e->getCode() . ' ' . $e->getMessage();
}
return $response;
}