char *来自FILE时有所不同

Question

My C程序在FILE中存储shell命令输出，将其传递给char数组并打印出来。

您不需要查看程序中的函数，因为问题出在main上。

我的shell中命令的输出是：

$ cmus-remote -Q | grep 'tag title' | sed s/'tag      title'/''/g
 The View From The Afternoon

gdb中的char值为：

34              fclose(tmp2);
(gdb) print title
$4 = 0x603010 " The View From The Afternoon\n"
(gdb) n
51              char *lyric = lyrics_get(artist, title);
(gdb) print title
$5 = 0x603010 " The View From The After\001\002"

这是代码

#include <stdlib.h>
#include <stdio.h>
#include <curses.h>
#include "/usr/include/glyr/glyr.h"
#include <unistd.h>
#include <string.h>

char *lyrics_get(char *a, char *b);

int main(void)
{

    FILE *tmp1;
    FILE *tmp2;
    char *artist;
    char *title;
    tmp1 = popen("cmus-remote -Q | grep 'tag artist' | sed s/'tag artist'/''/g | sed '1s/^.//'", "r");
    tmp2 = popen("cmus-remote -Q | grep 'tag title' | sed s/'tag title'/''/g", "r");

    fseek(tmp1, 0, SEEK_END);
    size_t size1 = ftell(tmp1);
    rewind(tmp1);
    artist = malloc((size1 +1) * (sizeof(char)));
    fread(artist, sizeof(char), size1, tmp1);
    fclose(tmp1);

    fseek(tmp2, 0, SEEK_END);
    size_t size2 = ftell(tmp2);
    rewind(tmp2);
    title = malloc((size2 +1) * (sizeof(char)));
    fread(title, sizeof(char), size2, tmp2)
    fclose(tmp2);

    char *lyric = lyrics_get(artist, title);
    printf("%s", title);
    printf("%s", artist);
    printf("%s", lyric);
    return 0;

}

char *lyrics_get(char *a, char *b)
{
    glyr_init();
    atexit (glyr_cleanup);
    GlyrQuery q;
    glyr_query_init (&q);
    glyr_opt_type (&q,GLYR_GET_LYRICS);

    glyr_opt_artist (&q, (a));
    glyr_opt_title  (&q, (b));
    glyr_opt_force_utf8 (&q, true);
    GLYR_ERROR err;
    GlyrMemCache * head = glyr_get (&q,&err,NULL);
    return (head->data);
    glyr_free_list(head);
    glyr_query_destroy(&q);
}

为什么会有所不同？