Question

我正在尝试将一些使用mysql的旧PHP代码转换为使用mysqli，

我更新的代码是：

function mysql_fetch_full_result_array($result){
global $dbc;

    $table_result=array();
    $r=0;
    while($row = mysqli_fetch_assoc($result)){
        $arr_row=array();
        $c=0;
        while ($c < mysqli_num_fields($result)) {       
            $col = mysqli_fetch_field($result);   
            $arr_row[$col -> name] = $row[$col -> name];           
            $c++;
        }   
        $table_result[$r] = $arr_row;
        $r++;
    }   
    return $table_result;
}

然而，在第一行之后，它只为每个值输出null，如此处所示，我确定我没有增加某些内容，但我不确定此处的位置或方式：

{"DOMAIN.COM":[{"image":"http:\/\/DOMAIN.COM\/photos\/grid_logo.jpg","source":"logo","user":"","printed":"","note":""},{"image":"http:\/\/DOMAIN.COM\/photos\/grid_block.jpg","source":"block","user":"","printed":"","note":""},{"image":"http:\/\/pbs.twimg.com\/media\/BlNvdcrCAAAlz8-.jpg","source":"twitter","user":"ObserveMeditate","printed":"0","note":"RT @IMSEngage: Moby (@thelittleidiot) sits down with the legendary @DAVID_LYNCH this Wednesday: http:\/\/t.co\/PMn9EHQVcp #IMSEngage http:\/\/t.\u2026"},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null},{"image":null,"source":null,"user":null,"printed":null,"note":null}]}

Answer 1

您尝试执行的操作与此相同（除了包含大量无关代码）：

while($row = mysqli_fetch_assoc($result)) {
    $table_result[] = $row;
}   
return $table_result;

或者也许：

while($row[] = mysqli_fetch_assoc($result)) { }   
return $row;

甚至只是：

$all_rows = mysqli_fetch_all($result, MYSQLI_ASSOC); //may still be server dependent

使用mysqli检索数组

1 个答案: