我更喜欢用VBA执行此操作,根据需要执行而不是公式,因为我有16000行。
电子表格在COL A中列出了几百个条目。我需要查看其中有多少在COL B中有不同的值
COL A COL B
A 1
A 2
A 1
A 1
A 2
A 1
A 1
A 1
B 1
B 1
B 1
B 1
B 1
现在返回COL B中唯一结果的计数,由COL A
索引COL A COL B
A 2
B 1
我从这开始,然后我的头开始旋转(我真的很讨厌VBA它根本没有点击我):
编辑 - 删除了我开始使用的垃圾,因为它对任何人都没有帮助。这就是我最终使用的必须修改@alter的答案只显示大于1的索引,然后将其输出到文本文件而不是msgbox(我第一次运行它时有数百个msgbox。
Sub CountUnique()
On Error GoTo ErrorHandler:
Dim keyMap As Object, values As Object
Dim key As String, value As String
Dim keysColumn As String, valuesColumn As String
Dim row As Long
Dim rowCount As Long
Dim item As Object
Dim outFile As String
myFile = "C:\usercount.txt"
Set keyMap = CreateObject("Scripting.Dictionary")
rowCount = ActiveSheet.UsedRange.Rows.Count
keysColumn = "C"
valuesColumn = "E"
For row = 2 To rowCount
key = Range(keysColumn & row).Text
value = Range(valuesColumn & row).Text
If keyMap.Exists(key) Then
Set values = keyMap.item(key)
If values.Exists(value) = False Then values.Add value, ""
Else
Set values = CreateObject("Scripting.Dictionary")
values.Add value, ""
keyMap.Add key, values
End If
Next row
Open myFile For Output As #1
For Each v In keyMap.keys
key = v
Set values = keyMap.item(key)
If values.Count > 1 Then
Write #1, key & ": " & values.Count
End If
Next v
Close #1
Exit Sub
ErrorHandler:
MsgBox "Something went wrong"
End Sub
答案 0 :(得分:1)
快速解决方案,只需使用2D字典。第一个维度是列A(您要索引的列),第二个维度是列B(值)。关于词典的好处是他们有一个" Exists"用于检查密钥是否已被使用的功能
Sub CountUnique()
On Error GoTo ErrorHandler:
Dim keyMap As Object, values As Object
Dim key As String, value As String
Dim keysColumn As String, valuesColumn As String
Dim row As Long
Dim rowCount As Long
Dim item As Object
Set keyMap = CreateObject("Scripting.Dictionary")
rowCount = ActiveSheet.UsedRange.Rows.Count
keysColumn = "A"
valuesColumn = "B"
For row = 2 To rowCount
key = Range(keysColumn & row).Text
value = Range(valuesColumn & row).Text
If keyMap.Exists(key) Then
Set values = keyMap.item(key)
If values.Exists(value) = False Then values.Add value, ""
Else
Set values = CreateObject("Scripting.Dictionary")
values.Add value, ""
keyMap.Add key, values
End If
Next row
For Each v In keyMap.keys
key = v
Set values = keyMap.item(key)
MsgBox key & ": " & values.Count
Next v
Exit Sub
ErrorHandler:
MsgBox "Something went wrong"
End Sub
答案 1 :(得分:1)
另一种方法:
Sub Tester()
CountUnique Range("A2:A10"), Range("d2")
End Sub
Sub CountUnique(rngIn As Range, rngOut As Range)
Dim d As Object
Dim c As Range, tmp, v, arr(), i As Long, ex, k
Set d = CreateObject("scripting.dictionary")
For Each c In rngIn.Cells
tmp = Trim(c.Value)
v = Trim(c.Offset(0, 1).Value)
If d.exists(tmp) Then
arr = d(tmp)
ex = False
For i = LBound(arr) To UBound(arr)
If v = arr(i) Then
ex = True
Exit For
End If
Next i
If Not ex Then
ReDim Preserve arr(LBound(arr) To UBound(arr) + 1)
arr(UBound(arr)) = v
d(tmp) = arr
End If
Else
ReDim arr(0 To 0)
arr(0) = v
d(tmp) = arr
End If
Next c
i = 0
For Each k In d.keys
rngOut.Offset(i, 0).Value = k
arr = d(k)
rngOut.Offset(i, 1).Value = Join(arr, ",")
rngOut.Offset(i, 2).Value = 1 + (UBound(arr) - LBound(arr))
i = i + 1
Next k
End Sub
答案 2 :(得分:1)
您应该考虑使用数据透视表。这将返回您正在寻找的最终结果。只需选择整个范围,创建一个数据透视表,并将两列放入"行标签"区域。
这消除了大量令人费解的VBA脚本的需要。