Question

未能比我承认的更长时间地破解这个。

我不认为这可能是一个不寻常的问题 - 当然mapping table troubles在SQL领域只有一打 - 所以我只会问，希望其他人可以从我的无知中受益。 / p>

我正在尝试将五个表拉在一起，以显示连接到主类别和子类别的产品。我想要显示的是产品表中的信息。

表格如下：

**products**
product_id (PK) | [other columns with product information]

**categories**
category_id (PK) | category_name

**sub_categories**
sub_category_id (PK) | sub_category_name

**products_and_categories**
pc_rel_id (PK) | pc_product_id (FK - products.product_id) | pc_category_id (FK -    categories.category_id)

**products_and_sub_categories**
psc_rel_id (PK) | psc_product_id (FK - products.product_id) | psc_sub_category_id (FK -    sub_categories.sub_category_id)

到目前为止，我毫无结果的尝试包括：

$getSCatProds = new QueryClass();
    $catSubArray['queryCategory'] = 'main category name';
    $catSubArray['querySubCategory'] = 'sub category name';

//PDO fetchAll(PDO::FETCH_ASSOC)

    $resultArray = $getSCatProds->fetchAllQuery("SELECT product_id FROM products
                   INNER JOIN (products_and_categories, products_and_sub_categories)
                       ON (products_and_categories.pc_product_id=products.product_id 
                       AND products_and_sub_categories.psc_product_id=products.product_id) 
                   INNER JOIN (categories, sub_categories)
                       ON (categories.category_id = products_and_categories.pc_category_id 
                       AND sub_categories.sub_category_id = products_and_sub_categories.psc_sub_category_id)
                   WHERE categories.category_name = :queryCategory
                       AND sub_categories.sub_category_name = :querySubCategory", $catSubArray);

    print_r($resultArray); //returns an empty array

和

//Query method and sent information same as in the above query

$resultArray = $getSCatProds->fetchAllQuery("SELECT product_id FROM products
               INNER JOIN (products_and_categories, products_and_sub_categories, categories, sub_categories)
                   ON (products_and_categories.pc_product_id=products.product_id 
                   AND products_and_sub_categories.psc_product_id=products.product_id) 
               WHERE categories.category_name = :queryCategory
                   AND sub_categories.sub_category_name = :querySubCategory", $catSubArray);

print_r($resultArray); 
//returns a stupendous number of product_id:s, 2030 of them to be exact.
//There are 2075 items in the products table ...

请给我可怜的小伙伴找一个正确的问题。

谢谢。

Answer 1

您需要为每个表单独进行连接。

SELECT p.product_id
FROM products AS p
JOIN products_and_categories AS pc ON p.product_id = pc.pc_product_id
JOIN categories AS c ON pc.pc_category_id = c.category_id
JOIN products_and_subcategories AS psc ON p.product_id = psc.psc_product_id
JOIN sub_categories AS sc ON psc.psc_sub_category_id = sc.sub_category_id
WHERE c.category_name = :queryCategory
AND sc.sub_category_name = :querySubCategory

MySQL加入多个映射表

1 个答案: