Question

是否可以将antlr4 python运行时与python 2.6一起使用，或者是最小化所需版本python 2.7？我想在python 2.6.6附带的CentOS 6.3上使用它。如果不可能，是否知道使用了python 2.7的哪些特性？

Answer 1

最后我可以自己回答这个问题。在centos6.3（有python 2.6.6）上使用antlr4-python2运行时是不可能的，我已经安装了它并尝试了this example。结果如下：

[lg@localhost py]$ python test.py data.txt 
Traceback (most recent call last):
  File "test.py", line 15, in <module>
    main(sys.argv)
  File "test.py", line 10, in main
    tree = parser.r()
  File "/home/lg/antlr/py/HelloParser.py", line 74, in r
    self.enterRule(localctx, 0, self.RULE_r)
  File "/usr/lib/python2.6/site-packages/antlr4/Parser.py", line 367, in enterRule
    self._ctx.start = self._input.LT(1)
  File "/usr/lib/python2.6/site-packages/antlr4/CommonTokenStream.py", line 85, in LT
    self.lazyInit()
  File "/usr/lib/python2.6/site-packages/antlr4/BufferedTokenStream.py", line 209, in lazyInit
    self.setup()
  File "/usr/lib/python2.6/site-packages/antlr4/BufferedTokenStream.py", line 212, in setup
    self.sync(0)
  File "/usr/lib/python2.6/site-packages/antlr4/BufferedTokenStream.py", line 134, in sync
    fetched = self.fetch(n)
  File "/usr/lib/python2.6/site-packages/antlr4/BufferedTokenStream.py", line 146, in fetch
    t = self.tokenSource.nextToken()
  File "/usr/lib/python2.6/site-packages/antlr4/Lexer.py", line 131, in nextToken
    tokenStartMarker = self._input.mark()
AttributeError: 'builtin_function_or_method' object has no attribute 'mark'
[lg@localhost py]$

Answer 2

您使用的示例写得不好。 input是内置Python函数的名称。给Lexer一个FileStream，它可能会起作用。

使用python 2.6的antlr4 python运行时

2 个答案: