Question

我想将图像上传到网络服务器。因为我已经编写了代码，但是当我将文件上传到网络服务器而不是文件名时，我将获得图像路径。

码

protected String sendFile(final Context context, final String url, final String params, String fileName, final File f) {
        DataOutputStream dos = null;
        int bytesRead = 0, bytesAvailable = 0, bufferSize;
        int maxBufferSize = 1024;
        byte[] buffer;
        String serverResponseMessage = null;
        String uploaded_file = fileName;


        URL url1 = null;
        try {

            FileInputStream fileInputStream = new FileInputStream(f);
            url1 = new URL(url + "?" + params);
            HttpURLConnection connection = (HttpURLConnection) url1.openConnection();
            connection.setRequestMethod("POST");
            connection.setDoInput(true);
            connection.setDoOutput(true);
            connection.setUseCaches(false);
            connection.setRequestProperty("Connection", "Keep-Alive");
            connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
            connection.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
            connection.setRequestProperty("uploaded_file", fileName);
            fileName = String.valueOf(f);
            //connection.setRequestProperty ("uploaded_file", "sample");
            dos = new DataOutputStream(connection.getOutputStream());
            dos.writeBytes(twoHyphens + boundary + lineEnd);

            dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\"hello" + fileName + "\"" + lineEnd);


            dos.writeBytes(lineEnd);


            bytesAvailable = fileInputStream.available(); // create a buffer of  maximum size

            bufferSize = Math.min(bytesAvailable, maxBufferSize);
            buffer = new byte[bufferSize];

            // read file and write it into form...
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);

            while (bytesRead > 0) {
                dos.write(buffer, 0, bufferSize);
                bytesAvailable = fileInputStream.available();
                bufferSize = Math.min(bytesAvailable, maxBufferSize);
                bytesRead = fileInputStream.read(buffer, 0, bufferSize);
            }

            // send multipart form data necesssary after file data...
            dos.writeBytes(lineEnd);
            dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

            dos.close();

            // Responses from the server (code and message)
            int serverResponseCode = connection.getResponseCode();
            serverResponseMessage = connection.getResponseMessage();

            StringBuffer b;
            int ch;
            InputStream is;
            is = connection.getInputStream();
            // retrieve the response from server

            b = new StringBuffer();
            while ((ch = is.read()) != -1) {
                b.append((char) ch);
            }
            String response = b.toString();
            Log.e("Response", "" + response);


        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (ProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
            Log.e("Error message", "" + e);
        }
        return serverResponseMessage;
    }

    protected File saveFile(Context context, int value, String name) {

        File directory = new File(Environment.getExternalStorageDirectory() + "/pocketDocs/Camera/Gallery/Others");
        if (!directory.exists()) {
            directory.mkdirs();
        }

        if (value == 0) {
            f = new File(Environment.getExternalStorageDirectory() + "/pocketDocs/Gallery", name);
            try {
                FileOutputStream out = new FileOutputStream(f);
                out.flush();
                out.close();
            } catch (Exception e) {
                e.printStackTrace();
            }

        }

        return f;
    }
}

当我使用

时

fileName = String.valueOf(f);
  dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\"hello" + fileName + "\"" + lineEnd);

在服务器端，我将文件名作为图像路径。

当我不使用时

fileName = String.valueOf(f);

我得到了正确的文件名，但我没有得到图片的扩展名。

现在我怎么能解决这个问题，因为peoblem在这一行

dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\"hello" + fileName + "\"" + lineEnd);

Answer 1

您在文件中使用String.valueOf()来获取其名称，它返回一个空字符串，因此无效。相反，您必须使用file.getName()获取文件名。

文件名未正确显示

1 个答案: