显示列中因子的整行数据

Question

我的数据格式如下：

ID  Species Sex
1   spA     M
2   spB     F
3   spA     Sex Required

我想写一行代码，它给出了包含＆＃34; Sex Required＆＃34;的所有行的整行。在性别专栏

我试过了：

df[df$Sex == "Sex Required",]

但它无法正常工作。我知道这可能很简单，但我是R.的新手。

Answer 1

尝试：

 df<- structure(list(ID = 1:3, Species = structure(c(1L, 2L, 1L), .Label = c("spA", 
 "spB"), class = "factor"), Sex = structure(c(2L, 1L, 3L), .Label = c("F", 
 "M", " Sex Required"), class = "factor")), .Names = c("ID", "Species", 
 "Sex"), class = "data.frame", row.names = c(NA, -3L))

我认为有一些空格，即“需要性别”，或“需要性别”

df[df$Sex == "Sex Required",]
#[1] ID      Species Sex    
#<0 rows> (or 0-length row.names)


df[grep("Sex Required", df$Sex),]
#       ID Species           Sex
# 3  3     spA  Sex Required

或者

library(stringr)
df$Sex <- str_trim(df$Sex)
df[df$Sex == "Sex Required",]
#  ID Species          Sex
#3  3     spA Sex Required