PHP Crypt河豚输出和Python crypt不同

Question

在PHP中使用crypt创建了一个散列密码，并希望在Python中使用crypt模块进行相同的散列。我怎么能这样做？

这是我的PHP代码：

function generateSalt($cost = 10) {
    if (!is_numeric($cost) || $cost < 4 || $cost > 31) {
        throw new CException(Yii::t('Cost parameter must be between 4 and 31.'));
    }
    // Get some pseudo-random data from mt_rand().
    $rand = '';
    for ($i = 0; $i < 8; ++$i) {
        $rand.=pack('S', mt_rand(0, 0xffff));
    }
    // Add the microtime for a little more entropy.
    $rand .= microtime();
    // Mix the bits cryptographically.
    $rand = sha1($rand, true);
    // Form the prefix that specifies hash algorithm type and cost parameter.
    $salt = '$2a$' . str_pad((int) $cost, 2, '0', STR_PAD_RIGHT) . '$';
    // Append the random salt string in the required base64 format.
    $salt .= strtr(substr(base64_encode($rand), 0, 22), array('+' => '.'));
    return $salt;
}

function _hashPassword($password, $salt) {
    return crypt($password, $salt);
}

$salt =  generateSalt();
$pass = _hashPassword('password', $salt);

echo $salt . '<br>'.PHP_EOL;
echo $pass . '<br>'.PHP_EOL;

输出：

$2a$10$Vz1UEa7iImWZ8WN1GVkPtH
$2a$10$Vz1UEa7iImWZ8WN1GVkPt.ZmpAHNOgoR6Xt68WAvT.1TkqaLgeFVu

在Python中尝试过：

import crypt

def generate_password_salt(cost=10):
    if not isinstance(cost, int) or cost < 4 or cost > 31:
        raise ValueError('Cost parameter must be between 4 and 31.')
    import random, time, hashlib, base64
    rand = ''
    for _ in range(12):
        rand += str(random.choice('ABCDE0123456789'))
    rand += str(time.time())
    sha1 = hashlib.sha1()
    sha1.update(rand)
    rand = sha1.digest()
    return base64.b64encode(rand)[:22].replace('+', '.')

salt = generate_password_salt()
print(salt)

crpt = crypt.crypt('password', '$2$a10$%s$' % salt)
print(crpt)

获得与PHP不同的输出：

UD8M0q9ufdsr/yqPvgUM2m
None

现在，我希望Python中的输出与上面的PHP相同