Question

我有大量的表数据（比如22k行）。这些22k行是从json文件填充的。我现在要做的是将这些数据导出为CSV。

     <html>
    <head>
    <link rel="stylesheet" type="text/css" href="a.css">
    </head>
    <body>
    <div class='mydiv'>    
        <textarea id="txt" class='txtarea'>

    // json datas here.. ( say , 22k rows
    </textarea>

        <button class='gen_btn'>Generate File</button>

    </div>
    </body>
    </html>


js file : 

$(document).ready(function() {
    $('button').click(function() {
        var data = $('#txt').val();
        if (data == '')


            return;

        JSONToCSVConvertor(data, "Data Excel", true);
    });
});

    function JSONToCSVConvertor(JSONData, ReportTitle, ShowLabel) {
        var arrData = typeof JSONData != 'object' ? JSON.parse(JSONData) : JSONData;

        var CSV = '';

        CSV += ReportTitle + '\r\n\n';



        if (ShowLabel) {
            var row = "";


            for (var index in arrData[0]) {


                row += index + ',';
            }

            row = row.slice(0, -1);


            CSV += row + '\r\n';
        }


        for (var i = 0; i < arrData.length; i++) {
            var row = "";


            for (var index in arrData[i]) {
                row += '"' + arrData[i][index] + '",';
            }

            row.slice(0, row.length - 1);


            CSV += row + '\r\n';
        }

        if (CSV == '') {
            alert("Invalid data");
            return;
        }


        var fileName = "MyReport_";

        fileName += ReportTitle.replace(/ /g, "_");


        var uri = 'data:text/csv;charset=utf-8,' + escape(CSV);


        var link = document.createElement("a");
        link.href = uri;

        link.style = "visibility:hidden";
        link.download = fileName + ".csv";

        document.body.appendChild(link);
        link.click();
        document.body.removeChild(link);
    }

如何编写一个js文件，将所有这些22k行导出到excel而不会导致浏览器崩溃？（它不应该显示杀页）。

Answer 1

看起来这个问题很老了..但如果有人还在寻找解决方案那么

这可能会有所帮助。

在这段代码中我使用blob来创建csv文件。

function JSONToCSVConvertor(JSONData, ReportTitle, ShowLabel) {     

    //If JSONData is not an object then JSON.parse will parse the JSON string in an Object
    var arrData = typeof JSONData != 'object' ? JSON.parse(JSONData) : JSONData;
    var CSV = '';    
    //This condition will generate the Label/Header
    if (ShowLabel) {
        var row = "";

        //This loop will extract the label from 1st index of on array
        for (var index in arrData[0]) {
            //Now convert each value to string and comma-seprated
            row += index + ',';
        }
        row = row.slice(0, -1);
        //append Label row with line break
        CSV += row + '\r\n';
    }

    //1st loop is to extract each row
    for (var i = 0; i < arrData.length; i++) {
        var row = "";
        //2nd loop will extract each column and convert it in string comma-seprated
        for (var index in arrData[i]) {
            row += '"' + arrData[i][index] + '",';
        }
        row.slice(0, row.length - 1);
        //add a line break after each row
        CSV += row + '\r\n';
    }

    if (CSV == '') {        
        alert("Invalid data");
        return;
    }   

    //this trick will generate a temp "a" tag
    var link = document.createElement("a");    
    link.id="lnkDwnldLnk";

    //this part will append the anchor tag and remove it after automatic click
    document.body.appendChild(link);

    var csv = CSV;  
    blob = new Blob([csv], { type: 'text/csv' }); 
    var csvUrl = window.webkitURL.createObjectURL(blob);
    var filename = 'UserExport.csv';
    $("#lnkDwnldLnk")
    .attr({
        'download': filename,
        'href': csvUrl
    }); 

    $('#lnkDwnldLnk')[0].click();    
    document.body.removeChild(link);
}

Answer 2

我想把这个放在这里因为我花了一些时间来完成所有这些评论，试图找到一种简单的方法将JSON数据转储导出到CSV：

$(document).ready(function() {
    var JSONData = $.getJSON("DataDump.php", function(data) {
        //Convert JSON to CSV
        var items = data;
        const replacer = (key, value) => value === null ? '' : value; // specify how you want to handle null values here
        const header = Object.keys(items[0]);
        let csv = items.map(row => header.map(fieldName => JSON.stringify(row[fieldName], replacer)).join(','));
        csv.unshift(header.join(','));
        csv = csv.join('\r\n');

        //Download as CSV
        var downloadLink = document.createElement("a");
        var blob = new Blob(["\ufeff", csv]);
        var url = URL.createObjectURL(blob);
        downloadLink.href = url;
        downloadLink.download = "DataDump.csv";   //Name File Here
        document.body.appendChild(downloadLink);
        downloadLink.click();
        document.body.removeChild(downloadLink);
    });
});

如何在没有浏览器崩溃的情况下将大量的json数据导出到CSV？

2 个答案: