我正在建立一个有预订的网站。我使用ajax将表单中的信息发送到另一个页面,该页面将信息插入到我的数据库中。为了使它更有用,我想在我的数据库中建立测试连接。用户填写所需的所有字段后,他将单击提交按钮,测试连接必须先检查,然后再发送数据。当连接失败时,它会告诉用户没有设置连接(可能是他的互联网连接丢失,或服务器本身失败)。这样,网站就会阻止提示用户发送他们的预订数据,但实际上并不是。
编辑:
这是我的运行和固定代码:
$("#esubmit2").click(function(){
var event2 = document.getElementsByName("eevent2")[0].value;
var engager2 = document.getElementsByName("eengager2")[0].value;
var contact2 = document.getElementsByName("econtact2")[0].value;
var eadd2 = document.getElementsByName("eeadd2")[0].value;
var venue2 = document.getElementsByName("evenue2")[0].value;
var datein2 = document.getElementsByName("edatein2")[0].value;
var message2 = document.getElementsByName("emessage2")[0].value;
var reg2 = /^(([^<>()[\]\\.,;:\s@\"]+(\.[^<>()[\]\\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
if(event2 == "" || event2 == " "){
$("#eevent2").focus();
return false;
}
else if(engager2 == "" || engager2 == " "){
$("#eengager2").focus();
return false;
}
else if(contact2 == "" || contact2 == " "){
$("#econtact2").focus();
return false;
}
else if(venue2 == "Venue:"){
$("#evenue2").focus();
return false;
}
else if(datein2 == "" || datein2 == " "){
$("#edatein2").focus();
return false;
}
else if(message2 == "" || datein2 == " "){
$("#emessage2").focus();
return false;
}
else if(eadd2 != ""){
if(reg2.test(eadd2) == false){
$("#eeadd2").focus();
$("#eeadd2").css("backgroundColor","#800517");
$("#eeadd2").css("color","#FFFFFF");
return false;
}
else{
sendreserve_event2(); // call function sendreserve()
return false;
}
}
else{
sendreserve_event2(); // call function sendreserve()
return false;
}
})
function sendreserve_event2(){ // send informations to database
var data_string = $("form#eform2").serialize(); // IMPORTANT
$.ajax({
type: "POST",
url: "submitreserve_eventpc.php",
data: data_string,
success: function(json) {
if(json == 1){
$("#eevent2").val("");
$("#eengager2").val("");
$("#econtact2").val("");
$("#eeadd2").val("");
$("#evenue2").val("Venue:");
$("#edatein2").val("");
$("#emessage2").val("");
$("#eeadd2").css("backgroundColor","#FFFFFF");
$("#eeadd2").css("color","#555");
alert("Reservation Successful!!! \n\nPlease wait for your reservation code to be send to your e-mail account or contact number.\n\nThank you!");
return false;
}
else{
alert("Sorry for the inconvenience but the connection to our database failed.\nPlease check you internet connection or refresh you page.\n\nIf one of the above failed please report to our admin.\nThank You.");
return false;
}
}//end success function
}); //end ajax call
return false; // IMPORTANT
}
submitreserve_eventpc.php:
if($test){
mysql_query("INSERT INTO tblevent(eventName,engager,contactNumber,emailAdd,venue,checkinDate,message) VALUES('$event2','$engager2','$contact2','$eadd2','$venue2','$datein2','$message2')");
$ok = 1;
}
else{
$ok = 0;
}
echo json_encode($ok);
如果您看到任何改进,请编辑。现在这满足了我的需求:)
答案 0 :(得分:1)
你应该这样做。
你的php.file
<?php
$con=mysql_connect('localhost','root','root');
if($con){
// do insertion data here into the database
$sql = "Insert into table query";
if($sql){
echo "Data inserted successfully";
}else{
echo "Sorry! some error occured ".mysql_error();
}
}else{
echo "Unable to connect to the server";
}
?>
答案 1 :(得分:0)
你可以尝试这样的事情。
function sendreserve_event2(){ // send informations to database
var data_string = $("form#eform2").serialize(); // IMPORTANT
$.ajax({
type: "POST",
url: "submitreserve_eventpc.php",
data: data_string
}).done(function(data) {
data = $.parseJSON(data);
message = data.message;
if (message == "success")
{
$("#eevent2").val("");
$("#eengager2").val("");
$("#econtact2").val("");
$("#eeadd2").val("");
$("#evenue2").val("Venue:");
$("#edatein2").val("");
$("#emessage2").text("");
$("#eeadd2").css("backgroundColor","#FFFFFF");
$("#eeadd2").css("color","#555");
$("#esubmit2").blur();
alert("Reservation Successful!!! \n\nPlease wait for your reservation code to be send to your e-mail account or contact number.\n\nThank you!");
} else {
console.log(message);
}
});
return false; // IMPORTANT
}
在您的PHP文件中可以更改为以下内容。
$myDatabase = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$myDatabase)
{
$message = 'Could not connect: ' . mysql_error();
} else {
$event2 = $_POST['eevent2'];
$engager2 = $_POST['eengager2'];
$contact2 = $_POST['econtact2'];
$eadd2 = $_POST['eeadd2'];
$venue2 = $_POST['evenue2'];
$datein2 = $_POST['edatein2'];
$message2 = $_POST['emessage2'];
mysql_query("INSERT INTO tblevent(eventName,engager,contactNumber,emailAdd,venue,checkinDate,message) VALUES('$event2','$engager2','$contact2','$eadd2','$venue2','$datein2','$message2')");
$message = 'success';
}
$response = array('message' => $message);
echo json_encode($response); // This is the data that your AJAX function gets in .done