Question

我在下面有一个foreach，当print_r或var_dumped显示正确的数据时，但是一旦我将$finalMenuDetails放入我需要的位置，它就会显示Array而不是清单。

的var_dump

array(3) {
  [0]=>
  string(6) "Item 1"
  [1]=>
  string(6) "item 2"
  [2]=>
  string(6) "item 3"
}
array(3) {
  [0]=>
  string(2) "23"
  [1]=>
  string(2) "90"
  [2]=>
  string(2) "23"
}

PHP

foreach($menuDetailsItem as $key => $value)
{
    $finalMenuDetails[] = $value. " ".$amount[$key] . '<br/>';
}

过程：

$menuName              = $_POST['menu'];
    $menuDetailsItem       = $_POST['item'];
    $menuDetailsItemAmount = $_POST['amount'];

    $menuResult = '';
    foreach ($menuDetailsItem as $key => $value) {
        $menuResult .= $value." ".$menuDetailsItemAmount[$key]."<br/>";
    }

    if(empty($errorMessage)) 
    {   
        $to = "";
        $subject = "Booking";
        $headers = "From: " . strip_tags($_POST['Email']) . "\r\n" . "Reply-To: ". strip_tags($_POST['Email']) . "\r\n" . "Content-Type: text/html; charset=ISO-8859-1\r\n" . //header("Location: http://redherringcatering.co.nz/Thankyou.html");
        $message = "\n" . "<strong>NAME:</strong>    ". $varName . "<br />" . "<br />"  . "<strong>CONTACT:</strong>     " . $varContact . "<br />" . "<br />" . "<strong>EMAIL:</strong>    ". $varEmail . "<br />" . "<br />"  ."<strong>COMPANY:</strong>     ". $varCompany . "<br />" . "<br />"  . "<strong>No. ATTENDING:</strong>    ".$varAttending . "<br />" . "<br />"  ."<strong>FUNCTION DATE:</strong>    ". $varFunction . "<br />" . "<br />"  ."<strong>FUNCTION DAY:</strong>     ". $varFunctionDay . "<br />" . "<br />"  ."<strong>DATE ORDERED:</strong>  ". $varOrdered . "<br />" . "<br />"  ."<strong>TIME REQUIRED:</strong>     ". $varTime . "<br />" . "<br />"  . "<strong>ONSITE:</strong>  ". $varOnsite . ", ". $varOnsite2 . "<br />" . "<br />"  ."<strong>INVOICE TO:</strong>     ". $varInvoice . "<br />" . "<br />" ."<strong>ADDRESS:</strong>\n". $varAddress . "<br />" . "<br />"  ."<strong>SPECIAL NEEDS:</strong>   ". $varSpecial . "<br />" . "<br />" . "<strong>ORDER DETAILS:</strong><br/><br/>".  $menuName . "<br/>"."<br/>"."<strong>Items:</strong><br/><br/>".print_r($menuResult) . "\n";

        mail($to,$subject,$message,$headers);


        exit;
    }

Answer 1

尝试这样的事情：

$item = array("item 1","item 2","item 3") ;
$amount = array("23","90","23") ;
$result_array = '';
foreach ($item as $key => $value) {
    $result_array .= $value." ".$amount[$key]."<br/>";
}
print_r($result_array);

<强>输出

item 1 23
item 2 90
item 3 23

显示阵列数据

1 个答案: