Question

我有两个网址（urlA和urlB），并且这两个网址都以相同的json格式返回给我json响应。下面是我的JSON字符串，我通过从urlA调用回来。为了理解目的，我只有三个reportRecords缩短了它。一般来说，它可能超过~500 reportRecords

{
   "aggRecords": {
      "reportRecords": [
         {
            "min": 0,
            "max": 12,
            "avg": 0.3699187,
            "count": 246,
            "sumSq": 571,
            "stddev": 1.4779372,
            "median": 0,
            "percentileMap": {
               "95": 4
            },
            "metricName": "TransactionDuration",
            "dimensions": {
               "env": "dev",
               "pool": "titan",
               "Name": "PostProcessing",
               "Type": "PostProcessing"
            },
            "value": 91
         },
         {
            "min": 0,
            "max": 23,
            "avg": 2.3991289E-4,
            "count": 1463031,
            "sumSq": 3071,
            "stddev": 0.045814946,
            "median": 0,
            "percentileMap": {
               "95": 0
            },
            "metricName": "TransactionDuration",
            "dimensions": {
               "env": "dev",
               "pool": "titan",
               "Name": "ResourceContext",
               "Type": "ResourceContext"
            },
            "value": 351
         },
         {
            "min": 0,
            "max": 1209,
            "avg": 1.9203402,
            "count": 7344636,
            "sumSq": 71832774,
            "stddev": 2.4683187,
            "median": 2,
            "percentileMap": {
               "95": 4
            },
            "metricName": "TransactionDuration",
            "dimensions": {
               "env": "dev",
               "pool": "titan",
               "Name": "Client::Sync",
               "Type": "Client::Sync"
            },
            "value": 14104200
         }
      ]
   }
}

同样地，我也通过调用urlB来获取另一个JSON响应，它与上面显示的json格式完全相同。现在使用下面的代码，我能够序列化来自urlA对象中的DataTransactionMetrics的json响应。

public class JSONParser {
    private static RestTemplate restTemplate = new RestTemplate();
    private static final Gson gson = new Gson();
    private static final String URLA = "urlA";
    private static final String URLB = "urlB";

    public static void main(String[] args) {
        String jsonTransactionLine = restTemplate.getForObject(URLA, String.class);
        System.out.println(jsonTransactionLine);

        JsonElement jelement = new JsonParser().parse(jsonTransactionLine);
        JsonObject jobject = jelement.getAsJsonObject();
        jobject = jobject.getAsJsonObject("aggRecords");
        JsonArray jarray = jobject.getAsJsonArray("reportRecords");

        Type type = new TypeToken<List<DataTransactionMetrics>>() {
        }.getType();
        List<DataTransactionMetrics> serializeRecord = gson.fromJson(jarray, type);

        // how can I serialize json data coming from URLB to serializeRecord object as well?
    }
}

以下是我的DataTransactionMetrics课程 -

public class DataTransactionMetrics {

    private String metricName;
    private Map<String, Integer> percentileMap;
    private String median;
    private String stddev;
    private String sumSq;
    private String count;
    private String avg;
    private String max;
    private String min;

    // getters here

    public Dimensions dimensions;

    class Dimensions {
        private String env;
        private String pool;
        @SerializedName("Name")
        private String name;

        // getters here
    }
}

问题陈述： -

如何在同一个serializeRecord对象中序列化来自urlB的json响应，以便来自url（urlA和urlB）的所有数据都存在于同一个serializeRecord对象中？这可能吗？

Answer 1

也可以对urlB执行相同操作并连接两个结果列表：

static final Type listOfMetricsType = new TypeToken<List<DataTransactionMetrics>>() {}.getType();

private List<DataTransactionMetrics> loadMetrics(String url) {
    String jsonString = restTemplate.getForObject(URLA, String.class);

    JsonObject json = new JsonParser().parse(jsonString).getAsJsonObject();
    JsonArray jarr = json.getAsJsonObject("aggRecords").getAsJsonArray("reportRecords");

    return gson.fromJson(jarr, listOfMetrics);
}

public static void main(String[] args) {
    List<DataTransactionMetrics> metrics = loadMetrics(URLA);
    metrics.addAll(loadMetrics(URLB));

    // metrics now contains all metrics (from URLA and URLB)
}

如何序列化来自同一对象中两个URL的json数据？

1 个答案: