我有一张桌子，我一直在收集用户的时钟，闹钟时间，这显示在日历上没问题。但是，现在我想看看所有用户的工作时间。
每次用户进入时，都会创建一条新记录。每次用户退出时，也会创建一条新记录。
下面的我的SQL代码允许我调出时钟输入和时钟输出时间：
DECLARE @StartDate DateTime;
DECLARE @EndDate DateTime;
DECLARE @AssumedShiftStartTime DateTime;
DECLARE @AssumedShiftEndTime DateTime;
DECLARE @EmployeeName nvarchar(200);
DECLARE @ShiftStart DateTime
DECLARE @ShiftEnd DateTime
-- Date format: YYYY-MM-DD
SET @StartDate = '2014-07-01 00:00:00'
SET @EndDate = DATEADD (DAY, 1, @StartDate); -- Add one day
SET @AssumedShiftEndTime = '18:00:00'
SET @AssumedShiftStartTime = '09:00:00'
SET @EmployeeName = 'Paul';
-------------- Get Clock IN / OUT TIMES -----------------
SELECT EmployeeAttendance.LastUpdate, EmployeeAttendance.ClockInTime, EmployeeAttendance.ClockOutTime
FROM EmployeeAttendance INNER JOIN
Membership ON EmployeeAttendance.UserId = Membership.UserId
WHERE EmployeeAttendance.LastUpdate >= @StartDate AND EmployeeAttendance.LastUpdate <= @EndDate
AND Membership.Username = @EmployeeName
其中给出了以下结果：
LastUpdate ClockInTime ClockOutTime
2014-07-01 08:48:08.650 2014-07-01 08:48:08.650 NULL
2014-07-01 18:04:39.943 NULL 2014-07-01 18:04:39.923
2014-07-02 08:48:08.680 2014-07-01 09:00:08.340 NULL
2014-07-02 18:04:39.343 NULL 2014-07-01 18:00:39.623
2014-07-03 08:48:08.620 2014-07-01 08:58:08.860 NULL
2014-07-03 18:04:39.455 NULL 2014-07-01 18:05:39.985
我真正想要实现的是返回以下结果的东西。
编辑：如果结果返回null，我想使用@AssumedShiftStartTime或@AssumedShiftEndTime来允许结果总计小时计算但很难，因为有两个单独的记录记录为时钟输入和时钟输出：
DATE CLOCK-IN-TIME CLOCK-OUT-TIME TOTAL-HOURS
2014-07-01 08:49 18:04 9 Hours 15 Mins
2014-07-02 09:00 18:00 9 Hours 00 Mins
2014-07-03 08:58 18:05 9 Hours 07 Mins
Total-This-Month
27 Hours 15 Mins
编辑：感谢您Sean Lange的帮助。在应用你的回复的帮助后，我得到以下输出，其中显示了两行代表Clock In和Clock Out。我试图确定如何获得一天结果的最佳方法，计算总小时数，合并下两个并计算小时数等等。我认为这比它需要的更复杂，也许是SQL逻辑的时间重新编码
2014-07-01 08:48:08.650 NULL NULL NULL
NULL 2014-07-01 18:04:39.923 NULL NULL
2014-07-02 08:54:03.483 NULL NULL NULL
NULL 2014-07-02 17:09:34.940 NULL NULL
2014-07-03 08:48:01.070 NULL NULL NULL
NULL 2014-07-03 18:12:11.487 NULL NULL
2014-07-04 08:48:07.983 NULL NULL NULL
NULL 2014-07-04 18:07:09.390 NULL NULL
2014-07-05 08:56:24.410 NULL NULL NULL
NULL 2014-07-05 14:19:12.800 NULL NULL
2014-07-08 08:44:56.727 NULL NULL NULL
NULL 2014-07-08 18:15:12.143 NULL NULL
2014-07-09 08:46:15.103 NULL NULL NULL
NULL 2014-07-09 17:10:46.327 NULL NULL
2014-07-10 08:57:14.733 NULL NULL NULL
NULL 2014-07-10 18:10:37.897 NULL NULL
2014-07-11 08:52:10.783 NULL NULL NULL
NULL 2014-07-11 18:08:58.580 NULL NULL
2014-07-12 08:56:20.073 NULL NULL NULL
NULL 2014-07-12 14:15:44.103 NULL NULL
2014-07-15 08:47:04.330 NULL NULL NULL
NULL 2014-07-15 18:10:05.800 NULL NULL
2014-07-16 08:56:34.490 NULL NULL NULL
NULL 2014-07-16 17:05:06.627 NULL NULL
2014-07-17 08:46:37.263 NULL NULL NULL
NULL 2014-07-17 18:06:08.840 NULL NULL
2014-07-18 08:52:56.200 NULL NULL NULL
NULL 2014-07-18 18:11:25.750 NULL NULL
2014-07-19 08:54:36.277 NULL NULL NULL
NULL 2014-07-19 14:15:09.620 NULL NULL
2014-07-22 08:56:30.623 NULL NULL NULL
NULL 2014-07-22 16:03:00.653 NULL NULL
2014-07-23 08:49:53.687 NULL NULL NULL
NULL 2014-07-23 17:07:37.943 NULL NULL
2014-07-24 08:52:08.690 NULL NULL NULL
2014-07-25 08:57:13.477 NULL NULL NULL
NULL 2014-07-25 18:09:01.793 NULL NULL
2014-07-26 08:53:42.597 NULL NULL NULL
NULL 2014-07-26 14:03:21.063 NULL NULL
任何帮助都将被感激地接受。
谢谢
答案 0 :(得分：1)
这样的帮助吗？
declare @Times table(ClockIn datetime, ClockOut datetime)
insert @Times
select '2014-07-01 08:49', '2014-07-01 18:04' union all
select '2014-07-01 09:00', '2014-07-01 18:00'
select *
, datediff(hour, ClockIn, ClockOut) - case when datediff(minute, ClockIn, ClockOut) % 60 > 0 then 1 else 0 end as MyHours
,datediff(minute, ClockIn, ClockOut) % 60 as MyMinutes
from @Times
答案 1 :(得分：1)
这里我们编写一些测试数据：
DECLARE @TimeSheet TABLE
(
EmpId INT,
LastUpdate DATETIME,
ClockInTime DATETIME,
ClockOutTime DATETIME
)
INSERT INTO @TimeSheet
VALUES
(201, '2014-07-01 08:48:08.650', '2014-07-01 08:48:08.650' ,NULL ),
(201, '2014-07-01 18:04:39.943', NULL ,'2014-07-01 18:04:39.923'),
(201, '2014-07-02 08:48:08.680', '2014-07-01 09:00:08.340' ,NULL ),
(201, '2014-07-02 18:04:39.343', NULL ,'2014-07-01 18:00:39.623'),
(201, '2014-07-03 08:48:08.620', '2014-07-01 08:58:08.860' ,NULL ),
(201, '2014-07-03 18:04:39.455', NULL ,'2014-07-01 18:05:39.985'),
(110, '2014-07-01 08:48:08.650', '2014-07-01 06:48:08.650' ,NULL ),
(110, '2014-07-01 18:04:39.943', NULL ,'2014-07-01 14:01:39.923'),
(110, '2014-07-02 08:48:08.680', '2014-07-01 07:10:08.340' ,NULL ),
(110, '2014-07-02 18:04:39.343', NULL ,'2014-07-01 14:00:39.623'),
(110, '2014-07-03 08:48:08.620', '2014-07-01 06:58:58.860' ,NULL ),
(110, '2014-07-03 18:04:39.455', NULL ,'2014-07-01 14:01:39.985');
现在让我们创建一个CTE来对我们的数据进行编号：
WITH TimeRows AS
(
SELECT *,
ROW_NUMBER() OVER (PARTITION BY EmpId, CAST(LastUpdate AS DATE) ORDER BY LastUpdate) RN
FROM @TimeSheet
)
现在我们查询CTE以查找我们的clockin和clockout时间：
SELECT T1.EmpId,
T1.ClockInTime,
T2.ClockOutTime,
DATEDIFF(HOUR, T1.ClockInTime, T2.ClockOutTime) AS DHour,
DATEDIFF(MINUTE, T1.ClockInTime, T2.ClockOutTime) % 60 AS DMinutes
FROM TimeRows T1
INNER JOIN TimeRows T2
ON T2.EmpId = T1.EmpId
AND T2.RN = T1.RN + 1
AND CAST(T2.LastUpdate AS DATE) = CAST(T1.LastUpdate AS DATE)
这是输出：
EmpId ClockInTime ClockOutTime DHour DMinutes
110 2014-07-01 06:48:08.650 2014-07-01 14:01:39.923 8 13
110 2014-07-01 07:10:08.340 2014-07-01 14:00:39.623 7 50
110 2014-07-01 06:58:58.860 2014-07-01 14:01:39.987 8 3
201 2014-07-01 08:48:08.650 2014-07-01 18:04:39.923 10 16
201 2014-07-01 09:00:08.340 2014-07-01 18:00:39.623 9 0
201 2014-07-01 08:58:08.860 2014-07-01 18:05:39.987 10 7