Question

我试图在Ruby中进行多次替换。我会用PHP做的：

$text = "bar foo baz doom?";
$before = ["bar", "foo", "baz"];
$after = ["goto", "if", "else"];
$result = preg_replace($before, $after, $text);
// output: goto if else doom?

在Ruby中，类似下面的内容给我一个错误：

text = "bar foo baz doom?"
before = [/bar/, /foo/, /baz/]
after = ['goto', 'if', 'else']
result = text.gsub(before, after)
# => Can't convert Array into Regexp

你能帮助我吗？

Answer 1

将Hash与#gsub一起使用： -

text = "bar foo baz doom?"
before = ["bar", "foo", "baz"]
after = ["goto", "if", "else"]

hash = Hash[before.zip(after)]
  #=> {"bar"=>"goto", "foo"=>"if", "baz"=>"else"}
text.gsub(/\w+/) { |m| hash[m] || m }
  #=> "goto if else doom?"

Answer 2

我认为红宝石中没有相应的方法。您可以zip before和after并逐步应用每个替换。这是一个示例，我使用dup来防止改变原始内容。

text = "bar foo baz doom?"
before = [/bar/, /foo/, /baz/]
after = ['goto', 'if', 'else']
result = text.dup
before.zip(after).each { |pattern, replace| result.gsub!(pattern, replace) }
result

Answer 3

text = "bar foo baz doom?"
before = [/bar/, /foo/, /baz/]
after = ['goto', 'if', 'else']

before.each_with_index do |reg, i|
  text.gsub!(reg, after[i])
end

Answer 4

text = "bar foo baz doom?"
before = [/bar/, /foo/, /baz/]
after = ['goto', 'if', 'else']
result = text.dup
before.each_index { |i| result.gsub!(before[i] ,after[i]) }
result

Answer 5

归档此

的另一种方式

output = text.split.map { |x| before.index(x) ? after[before.index(x)] : x }.join(' ')

output根据要求包含"goto if else doom?"。

Answer 6

您可以在ruby 1.9.2及更高版本中使用正则表达式来实现此目的。

class String
  def preg_replace(before, after)
    gsub Regexp.union(before), Hash[before.zip(after)]
  end
end


text = "bar foo baz doom?"
before = ["bar", "foo", "baz"]
after = ["goto", "if", "else"]
text.preg_replace before, after
#=> "goto if else doom?"

Ruby中的数组替换

6 个答案: