Question

我有一个名为shuffledDeck的数组，其中包含52个被调整的Int数字我希望单独处理每个玩家

func dealCards1(){
    for i in 0...25{
        comp1PlayDeck += shuffledDeck[i]
    }
}

不太确定我应该返回什么我这样做是为了学习不重要的东西只是想知道我应该为exmp

的函数声明做些什么

func dealCards1(Int: Array) -> Int: Array{}

我不知道如何返回阵列任何帮助将不胜感激谢谢！：d 这是到目前为止的完整代码

import Foundation

let comp1 = 1
let comp2 = 2

var dealDeck =     [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52]
var shuffledDeck: [Int]

var comp1PlayDeck = [Int]()
var comp2PlayDeck: [Int]

var comp1WinDeck: [Int]
var comp2WinDeck: [Int]

var comp1CurrCard: Int
var comp2CurrCard: Int



//functions
    //shuffles cards from dealDeck returns to shuffledDeck
func shuffle<T>(var list: Array<T>) -> Array<T> {
    for i in 0..<list.count {
        let j = Int(arc4random_uniform(UInt32(list.count - i))) + i
        list.insert(list.removeAtIndex(j), atIndex: i)
    }
    return list
}
//shuffle deck
 shuffledDeck = shuffle(dealDeck)

for num in shuffledDeck {
    println(num)
}
//deals to player one
func dealCards1() -> [Int] {
    for i in 0...25{
        comp1PlayDeck += shuffledDeck[i]
    }
    return comp1PlayDeck
}
//deals to player two
func dealCards2(){

}
comp1PlayDeck = dealCards1()

Answer 1

您是否在询问如何从函数中返回处理过的comp1PlayDeck？如果是这样，只需让函数返回一个Int数组，并在函数末尾返回comp1PlayDeck。

var comp1PlayDeck = [Int]()
func dealCards1() -> [Int] { 
    for i in 0...25{            
        comp1PlayDeck += shuffledDeck[i]
    }
    return comp1PlayDeck
}

迅速向一系列＆＃34;卡＆＃34;中的玩家发牌。

1 个答案: