拥有以下内容:
from lxml import html
import io
from lxml import etree
parser = etree.HTMLParser()
doc = etree.parse(io.FileIO("index.html"), parser)
i=1
total = []
aa = doc.xpath(".//body/table[10]")
for x in aa:
for j in x:
for k in j:
print type(k) #output is <type 'lxml.etree._Element'>
print k.text
html文件的一部分:
这将显示:
/Request_number_1
15
0
100.00%
1035 ms
923 ms
1407 ms
None
/Request_number_2
15
0
100.00%
966 ms
857 ms
1613 ms
None
如何通过此lxml元素进行迭代?我想检索以毫秒表示的第一个值(例如average_time_array = [1035 ms,966ms])
答案 0 :(得分:1)
如何使用此xpath表达式? .//body/table[1]/tr/td[5]
average_time_array = [td.text for td in doc.xpath(".//body/table[10]/tr/td[5]")]
print average_time_array