Question

我正在尝试建立一个房地产列表网站，并让用户能够按代理和郊区进行过滤。目前我收到以下消息： “您的SQL语法有错误;请查看与您的MySQL服务器版本对应的手册，以便在第1行的'$ sql1'附近使用正确的语法” 目前我只关注第一个过滤器工作，即代理商中的“J Blades”下降，这就是为什么其他人不完整或完全错误。

<!DOCTYPE html>

<meta charset="UTF-8" />
<title>Pharcourts</title>
<link href="global.css" rel="stylesheet" type="text/css"/>

<div id="container">

<div id="container-background">


    <div id="header">


    <div id="nav">
            <ul>
                <li class="home"><a href="index.php">Home</a></li>
                <li class="listings"><a href="staffornot.php">Listings</a></li>
                <li class="agents"><a href="agents.php">Agents</a></li>
                <li class="contact"><a href="contact.php">About/Contact</a></li>
                <li class="login"><a href="login.php">Staff Login</a></li>
            </ul>
    </div>


    </div>


    <div id="sidebar">

        <h2>On This Page:</h2>
        <ul>
            <li><a href="#listings">Listings</a></li>
        </ul>


    </div>


    <div id="content">


        <a id="listings"></a>
        <h1>Current Listings:</h1>
        <h3><a href='logout.php'>Logout<a></h3>

    <?php

        session_start();
        if(!isset($_SESSION['username'])){
        header("Location:Login.php");
        }

        $con=mysqli_connect("localhost", "root", "") or die(mysqli_error());
        mysqli_select_db($con,"alexdb") or die(mysqli_error());

        Print "<form action='listingsstaff.php' method='post'>";

        $sql1 = "SELECT * FROM tblhousingstock WHERE agent='J Blades'";

        Print "Agent";
        Print "<select name='filteragent'>";
        Print "<option value='SELECT * FROM tblhousingstock'>All</option>";
        Print '<option value="$sql1")>J Blades</option>';
        Print "<option value='SELECT * FROM tblhousingstock WHERE agent=D Astle'>D Astle</option>";
        Print "<option value='SELECT * FROM tblhousingstock WHERE agent=M Smith'>M Smith</option>";
        Print "</select>";


        Print "Suburb";

        $data1=mysqli_query($con,"SELECT tblhousingstock.add2 FROM tblhousingstock GROUP BY tblhousingstock.add2") or die(mysqli_error());


        Print "<select name='filtersuburb' style=width:80px>";
        Print "<option value='all'>All</option>";
        while($info1 = mysqli_fetch_array ($data1))
        {
        Print "<option value=".$info1['add2'].">".$info1['add2']."</option>";
        }

        Print "</select>";

        Print "<input type='submit'>";
        Print "</form>";




        $data2=mysqli_query($con, $_POST['filteragent']) or die(mysqli_error($con));


        Print "<table border cellpadding=3>";

        Print "<th>Address:</th><th>Suburb:</th><th>City:</th><th>Asking Price:</th><th>Number of Bathrooms:</th><th>Number of Bedrooms:</th><th>Agent:</th>";

        while($info2 = mysqli_fetch_array ($data2))
        {
        Print "<tr>";
        Print "<td>".$info2['add1']."</td>";
        Print "<td>".$info2['add2']."</td>";
        Print "<td>".$info2['add3']."</td>";
        Print "<td>$".$info2['price']."</td>";
        Print "<td>".$info2['bath']."</td>";
        Print "<td>".$info2['bed']."</td>";
        Print "<td>".$info2['agent']."</td>";
        }

        Print "</table>";

    ?></p>



    </div>


    <div id="footer">

    </div>


</div>
</div>

Answer 1

Print '<option value="$sql1")>J Blades</option>';

您实际上并未在此处进行查询，您只是将文本分配给变量。

编辑：

你还有很长的路要走这条路，但希望这能解决你认为错误的问题：

    ..........
Print "<form action='listingsstaff.php' method='post'>";
    Print "Agent";
    Print "<select name='filteragent'>";
    Print "<option value=\"SELECT * FROM tblhousingstock\">All</option>";
    Print "<option value=\"SELECT * FROM tblhousingstock WHERE agent='J Blades'\">J Blades</option>";
    Print "<option value=\"SELECT * FROM tblhousingstock WHERE agent='D Astle'\">D Astle</option>";
    Print "<option value=\"SELECT * FROM tblhousingstock WHERE agent='M Smith'\">M Smith</option>";
    Print "</select>";
    Print "Suburb";
    ..........

我只是改变了用引号和双引号括起select语句的方式。

通过下拉菜单过滤表格。您的SQL语法有错误;

1 个答案: