我有一个gridview,我已设置允许插入到我的表的下一行,但我有一个问题...我有2个插入语句和一个select语句,在插入后更新表视图完成。我将值插入两个表中...第一个更新人员信息,第二个表更新行程安排以将其包括在旅行中。
第二个语句是我遇到问题的地方......当一个新记录插入数据库时,会自动为一个人创建一个新的PersonID
,因为我将其设置为PK和标识符Person
表,但我不确定如何获取新创建的PersonID
并将其插入TripSchedule
表。
以下是我插入新用户的代码:
protected void AddNewCustomer(object sender, EventArgs e)
{
string nFirstName = ((TextBox)GridView1.FooterRow.FindControl("txtFirstName")).Text;
string nLastName = ((TextBox)GridView1.FooterRow.FindControl("txtLastName")).Text;
string nEmergency = ((TextBox)GridView1.FooterRow.FindControl("txtEmergency")).Text;
string nCell = ((TextBox)GridView1.FooterRow.FindControl("txtCell")).Text;
string nAge = ((TextBox)GridView1.FooterRow.FindControl("txtAge")).Text;
string nActivityCard = ((TextBox)GridView1.FooterRow.FindControl("txtActivityCard")).Text;
string nInitials = ((TextBox)GridView1.FooterRow.FindControl("txtInitials")).Text;
string nBoat = ((TextBox)GridView1.FooterRow.FindControl("txtBoat")).Text;
string nGroup = ((TextBox)GridView1.FooterRow.FindControl("txtGroup")).Text;
SqlConnection con = new SqlConnection(strConnString);
SqlCommand cmd = new SqlCommand();
cmd.CommandType = CommandType.Text;
cmd.CommandText = "insert into Person(FirstName, LastName, Emergency#, Cell#, Age, ActivityCard, CraftType, Initials, Group#) " +
"values(@FirstName, @LastName, @Emergency, @Cell, @Age, @ActivityCard, @Boat, @Initials, @Group);" +
"insert into TripSchedule(TripType, PersonID, Time, Date) values ('" + ddlTripType.SelectedItem + "', WHAT GOES HERE?, '" + ddlTripTime.SelectedItem + "', '" + TextBox1.Text + "');" +
"SELECT Person.PersonID, Person.FirstName AS FirstName, Person.LastName AS LastName, Person.Emergency# AS Emergency#, Person.Cell# AS Cell#, Person.Age AS Age, " +
"Person.ActivityCard AS ActivityCard, Person.CraftType AS CraftType, Person.Initials AS Initials, Person.Group# AS Group# " +
"FROM Person INNER JOIN " +
"TripSchedule ON Person.PersonID = TripSchedule.PersonID where TripSchedule.Date = '" + TextBox1.Text + "' and " +
"TripSchedule.Time = '" + ddlTripTime.SelectedItem + "' and TripSchedule.TripType = '" + ddlTripType.SelectedItem + "';";
cmd.Parameters.Add("@FirstName", SqlDbType.VarChar).Value = nFirstName;
cmd.Parameters.Add("@LastName", SqlDbType.VarChar).Value = nLastName;
cmd.Parameters.Add("@Emergency", SqlDbType.NChar).Value = nEmergency;
cmd.Parameters.Add("@Cell", SqlDbType.NChar).Value = nCell;
cmd.Parameters.Add("@Age", SqlDbType.NChar).Value = nAge;
cmd.Parameters.Add("@ActivityCard", SqlDbType.NChar).Value = nActivityCard;
cmd.Parameters.Add("@Initials", SqlDbType.NChar).Value = nInitials;
cmd.Parameters.Add("@Boat", SqlDbType.VarChar).Value = nBoat;
cmd.Parameters.Add("@Group", SqlDbType.VarChar).Value = nGroup;
GridView1.DataSource = GetData(cmd);
GridView1.DataBind();
}
答案 0 :(得分:2)
我个人会将此分为至少两个SqlCommand
次调用 - 一次插入Person
,另一次插入TripSchedule
。另外:你应该全部使用参数化查询 - 不仅仅是某些地方(而不是其他地方......)。
要获取新插入的PersonID
,请使用SCOPE_IDENTITY()
调用 - 如下所示:
SqlCommand cmd = new SqlCommand();
cmd.CommandType = CommandType.Text;
cmd.CommandText = "INSERT INTO dbo.Person(FirstName, LastName, Emergency#, Cell#, Age, ActivityCard, CraftType, Initials, Group#) " +
"VALUES(@FirstName, @LastName, @Emergency, @Cell, @Age, @ActivityCard, @Boat, @Initials, @Group);" +
"SELECT SCOPE_IDENTITY();";
cmd.Parameters.Add("@FirstName", SqlDbType.VarChar).Value = nFirstName;
cmd.Parameters.Add("@LastName", SqlDbType.VarChar).Value = nLastName;
cmd.Parameters.Add("@Emergency", SqlDbType.NChar).Value = nEmergency;
cmd.Parameters.Add("@Cell", SqlDbType.NChar).Value = nCell;
cmd.Parameters.Add("@Age", SqlDbType.NChar).Value = nAge;
cmd.Parameters.Add("@ActivityCard", SqlDbType.NChar).Value = nActivityCard;
cmd.Parameters.Add("@Initials", SqlDbType.NChar).Value = nInitials;
cmd.Parameters.Add("@Boat", SqlDbType.VarChar).Value = nBoat;
cmd.Parameters.Add("@Group", SqlDbType.VarChar).Value = nGroup;
conn.Open();
int newPersonID = (int)cmd.ExecuteScalar();
conn.Close();
由于此SqlCommand
调用只返回一行,一列(新插入的PersonID
),因此您可以轻松使用.ExecuteScalar()
方法 - 然后返回新插入的{{ 1}}作为此调用的结果。现在,您可以将数据插入PersonID
表格中(并再次使用所有参数进行此次调用!)。
或者:将这一切都包装到一个存储过程中,在内部处理所有这些T-SQL功夫。
或者更好的是:在这些日子和时代,我会亲自切换到像实体框架这样的ORM,使这一切更容易