Question

我正在尝试使用复选框进行过滤。问题是当我取消选择一些盒子时并提交值，再次选中所有框。我认为问题可以在这里

if (isset($_POST['option_meno']))

可能是什么问题？是的，我是新来的，所以任何想让我的代码更简单的想法也会帮助我。

谢谢。

<?php

// Make a MySQL Connection
$query_o_meno = "SELECT meno FROM uctovnictvo GROUP BY meno ORDER BY meno"; 

$result_meno = mysql_query($query_o_meno) or die(mysql_error());



?>
<form method="post">
<?php


if (isset($_POST['Filtrovat'])) { 

    // Print checked checkboxes
        echo "<strong>Meno:</strong>";
        echo "<br />";
    while($row = mysql_fetch_array($result_meno)){
        //I believe the problem is line below ----------------------------- 
        if (isset($_POST['option_meno'])) {
            echo "<input type='checkbox' name='option_meno[]' value='".$row['meno']."' checked />" . $row['meno'];
            echo "<br />";
            //}
        }
        else{
            echo "<input type='checkbox' name='option_meno[]' value='".$row['meno']."' / >" . $row['meno'];
            echo "<br />";
        }

    }
    }

else{
    $option_meno = array();
        echo "<strong>Meno:</strong>";
        echo "<br />";
    while($row = mysql_fetch_array($result_meno)){
        echo "<input type='checkbox' name='option_meno[]' value='".$row['meno']."' checked />" . $row['meno'];
        echo "<br />";
        $option_meno[] = $row['meno'];
        }   
    }


?>
<input type="submit" name="Filtrovat" value="Filtrovat" />
</form>

Answer 1

由于您正在执行name='option_meno[]'，$_POST['option_meno']将是一个数组。只要至少选中一个复选框，就会始终设置该数组。尝试这样的事情：

<?php

// Make a MySQL Connection
$query_o_meno = "SELECT meno FROM uctovnictvo GROUP BY meno ORDER BY meno"; 

$result_meno = mysql_query($query_o_meno) or die(mysql_error());



?>
<form method="post">
<?php


if (isset($_POST['Filtrovat'])) { 

    // Print checked checkboxes
        echo "<strong>Meno:</strong>";
        echo "<br />";
    while($row = mysql_fetch_array($result_meno)){
        //I believe the problem is line below ----------------------------- 
        if (isset($_POST['option_meno'][$row['meno']])) {
            echo "<input type='checkbox' name='option_meno[".$row['meno']."]' value='".$row['meno']."' checked='checked' />" . $row['meno'];
            echo "<br />";
            //}
        }
        else{
            echo "<input type='checkbox' name='option_meno[".$row['meno']."]' value='".$row['meno']."' / >" . $row['meno'];
            echo "<br />";
        }

    }
    }

else{
    $option_meno = array();
        echo "<strong>Meno:</strong>";
        echo "<br />";
    while($row = mysql_fetch_array($result_meno)){
        echo "<input type='checkbox' name='option_meno[".$row['meno']."]' value='".$row['meno']."' checked />" . $row['meno'];
        echo "<br />";
        $option_meno[] = $row['meno'];
        }   
    }


?>
<input type="submit" name="Filtrovat" value="Filtrovat" />
</form>

这样您就可以单独检查每个复选框。

注意：您应该始终完全声明checked属性，如下所示：checked='checked'

Answer 2

这未经过测试，但应该有效：

if (isset($_POST['Filtrovat'])) 
{ 
    // Print checked checkboxes
    echo "<strong>Meno:</strong>";
    echo "<br />";

    while($row = mysql_fetch_array($result_meno))
    {   
        $checked = "";
        if(isset($_POST['option_meno']))
        $checked = in_array($row['meno'],$_POST['option_meno'])?" 
                   checked = 'checked' ":"";

        echo "<input type='checkbox' name='option_meno[]' 
              value='".$row['meno']."' $checked / >" . $row['meno'];
        echo "<br />";
    }
}

PHP remeber选中复选框

2 个答案: