Question

在尝试做一些练习来学习java时，我写了一个简单的程序来计算工作小时数并给出应得的工资。

package horulycalc;

import java.util.Arrays;
import java.util.Scanner;

public class HorulyCalc {

    public static void main(String[] args) {
        Scanner param = new Scanner(System.in);
        String [] titles  = {"Developer","Designer","Data Entry","Manager","CEO"};
        System.out.println("Hello and welcome to Job Counter");
        System.out.println("Please enter you Job Title");
        String title = param.nextLine();
        while(!Arrays.asList(titles).contains(title)){
            System.out.println("Please enter valid Job Title"); 
            title = param.nextLine();
            if(Arrays.asList(titles).contains(title)){
                System.out.println("Please enter your Hours for this week :");
                String count = param.nextLine();
                System.out.printf("Your Salary is : $ %f",HoursMath(HourRate(title),Integer.parseInt(count)));
                break ;
            }
        }
    }

    public static int HourRate(String jobTitle){
        int rate = 0;
        switch(jobTitle){
            case "Developer":
                rate = 10 ;
                break;
            case "Designer":
                rate = 8 ;
                break ;
            case "Data Entry":
                rate = 6;
                break ;
            case "Manager":
                rate = 15 ;
                break;
            case "CEO":
                rate = 36;
                break ;
        }
        return rate ;
    }

    public static float HoursMath(int rate ,int count){
        float total ;
        total = rate * count ;
        return total ;
    }
}

如果我第一次添加错误的职位名称，程序运行正常，我的意思是输入不包含在职务名称数组中。

当我第一次输入有效的职位时，例如＆＃34; CEO＆＃34;程序中断和netbeans如何完成

Answer 1

那是因为当用户第一次输入有效值（在你的数组中）时你没有做任何事情。

    System.out.println("Please enter you Job Title");
    String title = param.nextLine(); // read title..
    while(!Arrays.asList(titles).contains(title)){ // while title is not present in array.
     }
 // nothing here--> what if title is present in the array / list?
  //So,Put this code here :. The below lines of code will be executed only hen you have a valid entry.
    System.out.println("Please enter your Hours for this week :");
    String count = param.nextLine();
    System.out.printf("Your Salary is : $ %f",HoursMath(HourRate(title),Integer.parseInt(count)));
            break

Answer 2

由于你的while循环已经测试了有效的标题，你也不应该在循环内测试它。

这更简单：

while(!Arrays.asList(titles).contains(title)){
    System.out.println("Please enter valid Job Title"); 
    title = param.nextLine();
}
System.out.println("Please enter your Hours for this week :");
String count = param.nextLine();
System.out.printf("Your Salary is : $ %f",HoursMath(HourRate(title),Integer.parseInt(count)));

你不必以这种方式摆脱循环。一旦你离开了循环，你知道你有一个有效的标题。

java循环中断if语句？

2 个答案: