Question

我有两张桌子。像这样;

Products table

id | brand | bla bla bla

Priority table

id | brand

我正在列出SELECT DISTINCT品牌FROM产品表BY ORDERING产品COUNT这样;

SELECT DISTINCT brand as bra, (SELECT COUNT(id) FROM Products WHERE brand = bra) as cnt FROM Products ORDER BY cnt DESC

结果是：

A Brand（65产品）
B Brand（43产品）
C Brand（23产品）
D Brand（17产品）

这是一条完美的工作线。但我想优先考虑一些品牌。列出顶部。

像这样：

S Brand（22产品）
X Brand（4个产品）
A Brand（65产品）
B Brand（43产品）
C Brand（23产品）
D Brand（17产品）

我用过这一行。但它没有用。

SELECT DISTINCT brand as bra, (SELECT COUNT(id) FROM Products WHERE brand = bra) as cnt, , (SELECT brand FROM Priority) as prior FROM Products ORDER BY prior ASC,cnt DESC

什么是真行？感谢...

--- --- EDIT 完全答案是：

SELECT p.brand as bra, count(p.id) as cnt
FROM products p
GROUP BY bra
ORDER BY bra IN (SELECT pri.brand FROM priority pri ORDER BY pri.brand ASC) DESC, mark ASC

Answer 1

您的第一个查询更清楚地写为：

SELECT b.brand as bra, count(p.id) as cnt
FROM bra b left outer join
     Products p
     on b.brand = p.brand
GROUP BY b.bra
ORDER BY cnt DESC;

仅在您担心不匹配的记录时才需要left outer join。如果这不是问题，编写查询的更简单方法是：

SELECT p.brand as bra, count(p.id) as cnt
FROM Products p
GROUP BY p.bra
ORDER BY cnt DESC;

如果您想按优先顺序排序，只需加入即可。这可能是您想要的：

SELECT p.brand as bra, count(p.id) as cnt
FROM bra b left outer join
     Products p
     on b.brand = p.brand left outer join
     Priority pr
     on b.brand = pr.brand
GROUP BY b.bra
ORDER BY pr.brand is not null desc, cnt DESC;

这将首先将品牌放在优先级表中。

Answer 2

使用此：

ORDER BY bra IN (SELECT brand FROM Priority) DESC, cnt DESC

MYSQL品牌按产品数量排序，但是

2 个答案: