PHP日历开始周与星期一（偏移）

Question

我正在为日历创建课程，我创建简单的月份预览。

问题：如何以星期一（或偏移）开始一周？

以下是它的样子：

如图所示，周从星期日开始。我想在周一开始一周。

这是我到目前为止所得到的：

代码：

<?php

class Calendar {

    public function __construct($year = '', $month = '') {

        $date = time();

        if (empty($year) OR empty($month)) {
            $year = date('Y', $date);
            $month = date('m', $date);
            $day = date('d', $date);
        }

        $first_day = mktime(0, 0, 0, $month, 1, $year);
        $title = date('F', $first_day);
        $day_of_week = date('D', $first_day);

        switch ($day_of_week) {
            case "Sun": $blank = 0;
                break;
            case "Mon": $blank = 1;
                break;
            case "Tue": $blank = 2;
                break;
            case "Wed": $blank = 3;
                break;
            case "Thu": $blank = 4;
                break;
            case "Fri": $blank = 5;
                break;
            case "Sat": $blank = 6;
                break;
        }

        $days_in_month = cal_days_in_month(0, $month, $year);

        echo '<table border=1 width=394>';

        echo '<tr>';
        echo '<th colspan=60>' . $title . ' ' . $year . '</th>';
        echo '</tr>';

        echo '<tr>';
        echo '<td width=62>Sun</td>';
        echo '<td width=62>Mon</td>';
        echo '<td width=62>Tue</td>';
        echo '<td width=62>Wed</td>';
        echo '<td width=62>Thu</td>';
        echo '<td width=62>Fri</td>';
        echo '<td width=62>Sat</td>';
        echo '</tr>';

        $day_count = 1;

        while ($blank > 0) {
            echo '<td></td>';
            $blank = $blank - 1;
            $day_count++;
        }

        $day_num = 1;

        while ($day_num <= $days_in_month) {

            echo '<td>' . $day_num . '</td>';
            $day_num++;
            $day_count++;

            if ($day_count > 7) {
                echo '</tr><tr>';
                $day_count = 1;
            }
        }

        while ($day_count > 1 && $day_count <= 7) {
            echo '<td> </td>';
            $day_count++;
        }

        echo '</tr>';

        echo '</table>';
    }

}

$c = new Calendar(2014, 6);

Answer 1

尝试这样的事情：

class Calendar {

    public function __construct($year = '', $month = '') {

        $date = time();

        if (empty($year) OR empty($month)) {
            $year = date('Y', $date);
            $month = date('m', $date);
            $day = date('d', $date);
        }

        $first_day = mktime(0, 0, 0, $month, 1, $year);
        $title = date('F', $first_day);
        $day_of_week = date('D', $first_day);

         switch ($day_of_week) {
            case "Mon": $blank = 0;
                break;
            case "Tue": $blank = 1;
                break;
            case "Wed": $blank = 2;
                break;
            case "Thu": $blank = 3;
                break;
            case "Fri": $blank = 4;
                break;
            case "Sat": $blank = 5;
                break;
            case "Sun": $blank = 6;
                break;
        }

        $days_in_month = cal_days_in_month(0, $month, $year);

        echo '<table border=1 width=394>';

        echo '<tr>';
        echo '<th colspan=60>' . $title . ' ' . $year . '</th>';
        echo '</tr>';

        echo '<tr>';
        echo '<td width=62>Mon</td>';
        echo '<td width=62>Tue</td>';
        echo '<td width=62>Wed</td>';
        echo '<td width=62>Thu</td>';
        echo '<td width=62>Fri</td>';
        echo '<td width=62>Sat</td>';
        echo '<td width=62>Sun</td>';
        echo '</tr>';

        $day_count = 1;

        while ($blank > 0) {
            echo '<td></td>';
            $blank = $blank - 1;
            $day_count++;
        }

        $day_num = 1;

        while ($day_num <= $days_in_month) {

            echo '<td>' . $day_num . '</td>';
            $day_num++;
            $day_count++;

            if ($day_count > 7) {
                echo '</tr><tr>';
                $day_count = 1;
            }
        }

        while ($day_count > 1 && $day_count <= 7) {
            echo '<td> </td>';
            $day_count++;
        }

        echo '</tr>';

        echo '</table>';
    }

}

$c = new Calendar(2014, 6);

<强>输出