Question

如何使用包含一个字段的SQL查询，如果该字段包含的值为＆＃39; 90＆＃39; AND＆＃39; 99＆＃39;，结果会将A连接到它？

最终输出将如下所示。

91A
92A
93A
94A
95A

我试过了。

SELECT
tblgrade.fld1stGrade ,'A'
FROM
tblgrade WHERE tblgrade.fld1stGrade BETWEEN '90' AND '99'

Answer 1

如果您的实现是在SQL Server中，请尝试以下操作。

SELECT
tblgrade.fld1stGrade +'A'
FROM
tblgrade WHERE CAST(tblgrade.fld1stGrade as int) >= 90 
and cast(tblgrade.fld1stGrade as int) <= 99;

对于MySQL实现，请使用以下内容。

select concat(tblgrade.fld1stGrade, 'A') from tblgrade
where tblgrade.fld1stGrade >= 90 and tblgrade.fld1stGrade <= 99;

对于MySQL中的多类别比较，请使用以下内容。

select 
case
  when tblgrade.fld1stGrade >=90 and tblgrade.fld1stGrade <= 99 
     then concat(tblgrade.fld1stGrade, 'A')
  when tblgrade.fld1stGrade >=80 and tblgrade.fld1stGrade <= 89 
     then concat(tblgrade.fld1stGrade, 'B')
  when tblgrade.fld1stGrade >=70 and tblgrade.fld1stGrade <= 79 
     then concat(tblgrade.fld1stGrade, 'C')
  else concat(details, 'D')
  end
  as Grade
from supportContacts;

Answer 2

你可以试试这个：

SELECT tblgrade.fld1stGrade + 'A' AS letter_grade FROM tblgrade 
WHERE tblgrade.fld1stGrade BETWEEN '90' AND '99'

连接＆＃39; A＆＃39;用SQL查询

2 个答案: