Question

有人可以帮我这张桌子吗？

col1    col2
0       1
0       1
1       0
1       1
2       0
2       1
3       1
3       1

（http://sqlfiddle.com/#!2/67d076）

我想从第一列中选择不同的值，并过滤掉第二列中具有零的值。结果应该是以下列表：[0,3]

Answer 1

select distinct col1 from test where 
    col1 not in (select col1 from test where col2 = 0)

Answer 2

这听起来像是在寻找像这样的查询：

SELECT DISTINCT `col1`
FROM `test`
WHERE `col1` NOT IN (
  SELECT `col1`
  FROM `test`
  WHERE `col2` = 0)

或使用JOIN，如下所示：

SELECT DISTINCT a.`col1`
FROM `test` a
LEFT JOIN `test` b ON a.`col1` = b.`col1` AND b.`col2` = 0
WHERE b.`col1` IS NULL

Demonstration

Answer 3

select col1
from tab
group by col1
having count(case when col2 = 0 then col2 end) = 0 -- only those where no zero exists

Answer 4

select col1
from test
group by col1
having min(col2) <> 0

测试：http://sqlfiddle.com/#!2/67d076/26/0

如果col2的值低于0，您可以使用：

select col1
from test
group by col1
having group_concat(col2) not like '%,0%'
   and group_concat(col2) not like '%0,%'
   and group_concat(col2) <> '0'

选择不同的行并应用过滤器

4 个答案: