我在设置新的Hibernate项目时遇到了一个非常基本的问题。
我有一个实体如下：
@Entity(name = "Player")
public class PlayerEntity implements Serializable {
private static final long serialVersionUID = 6584040856373261900L;
@Id
private long id;
@Column
private String forename;
@Column
private String surname;
@Column
private String team;
@Column
@Enumerated(EnumType.STRING)
private Position position;
@Column
private boolean selected;
@Column
private int totalPoints;
public PlayerEntity() {
}
public PlayerEntity(final long id, final String forename, final String surname, final String team,
final Position position, final boolean selected, final int totalPoints) {
this.id = id;
this.forename = forename;
this.surname = surname;
this.team = team;
this.position = position;
this.selected = selected;
this.totalPoints = totalPoints;
}
/**
* @return the id
*/
public long getId() {
return id;
}
/**
* @param id the id to set
*/
public void setId(long id) {
this.id = id;
}
/**
* @return the forename
*/
public String getForename() {
return forename;
}
/**
* @param forename the forename to set
*/
public void setForename(String forename) {
this.forename = forename;
}
/**
* @return the surname
*/
public String getSurname() {
return surname;
}
/**
* @param surname the surname to set
*/
public void setSurname(String surname) {
this.surname = surname;
}
/**
* @return the team
*/
public String getTeam() {
return team;
}
/**
* @param team the team to set
*/
public void setTeam(String team) {
this.team = team;
}
/**
* @return the position
*/
public Position getPosition() {
return position;
}
/**
* @param position the position to set
*/
public void setPosition(Position position) {
this.position = position;
}
/**
* @return the selected
*/
public boolean isSelected() {
return selected;
}
/**
* @param selected the selected to set
*/
public void setSelected(boolean selected) {
this.selected = selected;
}
/**
* @return the totalPoints
*/
public int getTotalPoints() {
return totalPoints;
}
/**
* @param totalPoints the totalPoints to set
*/
public void setTotalPoints(int totalPoints) {
this.totalPoints = totalPoints;
}
一个访问数据的数据服务如下：
public class PlayerDataServiceJpa implements PlayerDataService {
@PersistenceContext
private EntityManager entityManager;
public void addPlayers(final List<Player> players) {
for (final Player domainPlayer : players) {
final PlayerEntity entityPlayer = new PlayerEntity();
BeanUtils.copyProperties(domainPlayer, entityPlayer);
entityManager.persist(entityPlayer);
}
}
public List<Player> getPlayers() {
final List<Player> domainPlayers = new ArrayList<Player>();
final List<PlayerEntity> entityPlayers = entityManager.createQuery("SELECT tc FROM PlayerEntity tc", PlayerEntity.class).getResultList();
for (final PlayerEntity entityPlayer : entityPlayers) {
final Player domainPlayer = new Player();
BeanUtils.copyProperties(entityPlayer, domainPlayer);
domainPlayers.add(domainPlayer);
}
return domainPlayers;
}
然后我尝试按如下方式对数据服务进行单元测试：
@Transactional
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(value = {"/hsqlDatasourceContext.xml", "/testApplicationContext.xml"})
public class PlayerDataServiceJpaTest {
@PersistenceContext
private EntityManager entityManager;
@Autowired
@Qualifier(value = "playerDataServiceJpa")
private PlayerDataServiceJpa playerDataServiceJpa;
@Test
public void testGetPlayers() {
// arrange
final PlayerEntity player = TestDataUtil.createEntityPlayer(1);
entityManager.persist(player);
PlayerEntity find = entityManager.find(PlayerEntity.class, TestDataUtil.PLAYER_1_ID);
assertThat(find).isNotNull();
assertThat(find.getForename()).isEqualTo(TestDataUtil.PLAYER_1_FORENAME);
// act
final List<Player> players = playerDataServiceJpa.getPlayers();
// assert
assertThat(players).hasSize(1);
final Player retrievedPlayer = players.get(0);
assertThat(retrievedPlayer.getId()).isEqualTo(TestDataUtil.PLAYER_1_ID);
assertThat(retrievedPlayer.getForename()).isEqualTo(TestDataUtil.PLAYER_1_FORENAME);
assertThat(retrievedPlayer.getSurname()).isEqualTo(TestDataUtil.PLAYER_1_SURNAME);
assertThat(retrievedPlayer.getTeam()).isEqualTo(TestDataUtil.TEST_TEAM);
assertThat(retrievedPlayer.getTotalPoints()).isEqualTo(TestDataUtil.PLAYER_1_POINTS);
}
@Test
public void testAddPlayers() {
// arrange
final Player player1 = TestDataUtil.createModelPlayer(1);
final Player player2 = TestDataUtil.createModelPlayer(2);
// act
playerDataServiceJpa.addPlayers(Arrays.asList(player1, player2));
// assert
final List<Player> players = playerDataServiceJpa.getPlayers();
assertThat(players).hasSize(2);
final Player retrievedPlayer = players.get(0);
assertThat(retrievedPlayer.getId()).isEqualTo(TestDataUtil.PLAYER_1_ID);
assertThat(retrievedPlayer.getForename()).isEqualTo(TestDataUtil.PLAYER_1_FORENAME);
assertThat(retrievedPlayer.getSurname()).isEqualTo(TestDataUtil.PLAYER_1_SURNAME);
assertThat(retrievedPlayer.getTeam()).isEqualTo(TestDataUtil.TEST_TEAM);
assertThat(retrievedPlayer.getTotalPoints()).isEqualTo(TestDataUtil.PLAYER_1_POINTS);
}
但是，当我运行单元测试时，代码的持久部分似乎可以工作，但是当查询运行时，我得到以下内容：
org.hibernate.hql.internal.ast.QuerySyntaxException: PlayerEntity is not mapped
at org.hibernate.hql.internal.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:189)
at org.hibernate.hql.internal.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:109)
我的persistence.xml文件位于src / test / resources / META-INF中
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd">
<persistence-unit name="jpaData" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>aaa.bbb.ccc.entity.PlayerEntity</class>
</persistence-unit>
</persistence>
hsqlDatasourceContext.xml文件看起来像
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context"
xmlns:jee="http://www.springframework.org/schema/jee" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jaxrs="http://cxf.apache.org/jaxrs" xmlns:cxf="http://cxf.apache.org/core"
xsi:schemaLocation="http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd http://cxf.apache.org/jaxrs http://cxf.apache.org/schemas/jaxrs.xsd http://cxf.apache.org/core http://cxf.apache.org/schemas/core.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd"
xmlns:jdbc="http://www.springframework.org/schema/jdbc">
<!-- HSQLDB datasource -->
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="org.hsqldb.jdbcDriver" />
<property name="url" value="jdbc:hsqldb:mem:ex;sql.syntax_mys=true" />
<property name="username" value="sa" />
<property name="password" value="" />
</bean>
<bean id="jpaProperties" class="org.springframework.beans.factory.config.PropertiesFactoryBean">
<property name="properties">
<props>
<prop key="hibernate.hbm2ddl.auto">update</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitName" value="jpaData" />
<property name="dataSource" ref="dataSource" />
<property name="jpaProperties" ref="jpaProperties" />
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean id="persistenceProvider" class="org.hibernate.ejb.HibernatePersistence" />
</beans>
此问题似乎与以下问题JPA mapping: "QuerySyntaxException: foobar is not mapped..."非常相似，但在我的SELECT语句中情况正确。
有趣的是，如果我执行entityManager.find(PlayerEntity.class, 1l);，则会找到已保存的实体。
有没有人对问题是什么有任何想法？我花了很长时间才找到解决方案。
答案 0 :(得分：2)
Doh - 代表我的男生错误....
@Entity(name = "Player")
应该是......
@Entity
@Table(name = "Player")