Question

我正在尝试构建链接列表，但在编译代码时出现以下错误：

In file included from linkedlist.c:1:
linkedlist.h:9: warning: 'struct list_t' declared inside parameter list
linkedlist.h:9: warning: its scope is only this definition or declaration, which is probably not what you want
linkedlist.h:12: warning: 'struct list_t' declared inside parameter list
linkedlist.c: In function 'main':
linkedlist.c:11: warning: passing argument 2 of 'execute_choice' from incompatible pointer type
linkedlist.c: At top level:
linkedlist.c:28: error: conflicting types for 'execute_choice'
linkedlist.h:9: error: previous declaration of 'execute_choice' was here
linkedlist.c:56: error: conflicting types for 'create_node_in_linked_list'
linkedlist.h:12: error: previous declaration of 'create_node_in_linked_list' was here
linkedlist.h:9: warning: 'struct list_t' declared inside parameter list
linkedlist.h:9: warning: its scope is only this definition or declaration, which is probably not what you want
linkedlist.h:12: warning: 'struct list_t' declared inside parameter list
make: *** [all] Error 1

但是，我检查了我的源文件和头文件，'execute_choice'函数在两者中都有匹配的声明。这是我的源文件和头文件：

源文件：

#include "linkedlist.h"

int main (void)
{
    int choice;
    list_t* list;
    list = (list_t*)sizeof(list_t);

    while (1) {
        choice = display_menu_choices();
        execute_choice(choice, list);
    }
}

int display_menu_choices(void)
{
    int menu_choice;

    printf ("Please select from the following options\n");
    printf ("0. Exit program\n");
    printf ("1. Generate a linkedlist\n");
    printf ("2. Sort a linkedlist\n");
    scanf ("%d", &menu_choice);

    return menu_choice;
}

void execute_choice(int menu_choice, list_t* list)
{
    switch (menu_choice) {
        case GEN_LL:
        generate_linked_list();
        break;

        case SORT_LL:
        sort_linked_list();
        break;

        case EXIT:
        exit(0);
    }

    return;
}

void generate_linked_list(void)
{
    return;
}

void sort_linked_list(void)
{
    return;
}

void create_node_in_linked_list(list_t* list)
{
    return;
}

标题

#include <stdlib.h>
#include <stdio.h>

#define EXIT 0
#define GEN_LL 1
#define SORT_LL 2

int display_menu_choices(void);
void execute_choice(int, struct list_t*);
void generate_linked_list(void);
void sort_linked_list(void);
void create_node_in_linked_list(struct list_t*);

typedef struct node_t{
    struct node_t* current;
    struct node_t* next;
    int value;
} node_t;

typedef struct list_t{
    struct node_t* start;
} list_t;

此外，欢迎提示！请批评我的代码但是你觉得有必要 - 如果没有人指出他们，我永远不会从错误中吸取教训=）谢谢!!!

Answer 1

在尝试使用之前，您必须声明类型。

因此，如果在函数原型之前移动struct definitions / typedef，编译器应该停止抱怨隐式/冲突定义。

Answer 2

头文件中的内容顺序错误。 typedef应出现在函数定义之前。所以移动

typedef struct node_t{
  struct node_t* current;
  struct node_t* next;
  int value;
} node_t;

typedef struct list_t{
  struct node_t* start;
} list_t;

之前

int display_menu_choices(void);
void execute_choice(int, struct list_t*);

编译器抱怨冲突的类型

2 个答案: