Question

以下是mytable的样子：

+-----------------+-----------+-------------+------------------+
|      Time       | EventType | MachineName | UserDisplayName  |
+-----------------+-----------+-------------+------------------+
| 7/22/2014 6:52  | CONNECTED | MACH-10     | alice.brown      |
| 7/22/2014 6:52  | PENDING   | MACH-10     | alice.brown      |
| 7/22/2014 9:09  | PENDING   | MACH-2      | mike.hensworth   |
| 7/22/2014 6:58  | CONNECTED | MACH-2      | mike.hensworth   |
| 7/22/2014 6:57  | PENDING   | MACH-2      | mike.hensworth   |
| 7/22/2014 7:00  | CONNECTED | MACH-3      | will.garden      |
| 7/22/2014 6:59  | PENDING   | MACH-3      | will.garden      |
| 7/22/2014 5:30  | PENDING   | MACH-3      | will.garden      |
| 7/22/2014 11:20 | CONNECTED | MACH-4      | kent.clark.admin |
| 7/22/2014 11:20 | PENDING   | MACH-4      | kent.clark.admin |
| 7/22/2014 9:28  | CONNECTED | MACH-5      | inigo.montoya    |
| 7/22/2014 9:28  | PENDING   | MACH-5      | inigo.montoya    |
| 7/22/2014 9:15  | PENDING   | MACH-123    | inigo.montoya    |
| 7/22/2014 12:37 | CONNECTED | P-002       | joseph.smith     |
| 7/22/2014 12:36 | PENDING   | P-002       | joseph.smith     |
| 7/22/2014 9:43  | CONNECTED | P-005       | penny.pennyworth |
| 7/22/2014 9:41  | PENDING   | P-005       | penny.pennyworth |
| 7/22/2014 5:41  | CONNECTED | P-006       | thor.zeus        |
| 7/22/2014 5:40  | PENDING   | P-006       | thor.zeus        |
+-----------------+-----------+-------------+------------------+

情况是人（UserDisplayName）正在登录到计算机（MachineNames）。 Eventtype PENDING是登录的开始，EventType CONNECTED是成功连接。

基本上，我需要用户登录计算机所需的平均时间。我没有很好的方法将PENDING状态与CONNECTED状态相关联，因此我尝试计算CONNECTED状态与PENDING状态之间的时差给定MachineName的最新inigo.montoya EventType。

我不知道该怎么做，而这就是这个问题的关键。

但是我也遇到了我想克服和认识的问题。

（例如，PENDING）有时用户在一台计算机上启动PENDING，然后在需要很长时间时放弃，并在一秒钟内开始第二次CONNECTED机。列出的PENDING没有关闭第一个MACH-3事件。我想确定这些事件。
（例如，PENDING）有时CONNECTED永远不会成为机器上的PENDING，并且用户可以某种方式启动第二个{{1}}如预期。我想确定这些事件。

Answer 1

我认为这应该做你想要的：

with successes as
 (select x.userdisplayname,
         x.machinename,
         x.time as connection_time,
         y.time as pending_time,
         datediff(mi, y.time, x.time) as mins_between
    from mytable x
    join mytable y
      on x.userdisplayname = y.userdisplayname
     and x.machinename = y.machinename
   where x.eventtype = 'CONNECTED'
     and y.eventtype = 'PENDING'
     and y.time = (select max(z.time)
                     from mytable z
                    where z.userdisplayname = y.userdisplayname
                      and z.machinename = y.machinename
                      and z.time < y.time))
select y.userdisplayname, y.machinename, null, y.time, null
  from mytable y
  left join successes s
    on y.userdisplayname = s.userdisplayname
   and s.machinename = y.machinename
   and y.time = s.pending_time
 where s.connection_time is null
   and y.eventtype = 'PENDING'
union all
select * from successes

请注意，具有空值的行表示连接尝试失败。

我怎样才能获得最新的不同活动？

1 个答案: