Question

我正在尝试使用Twitter API列出趋势主题。在调用我的函数并分配给＆＃34; X＆＃34; （然后打印＆＃34; X＆＃34;）我返回（用JSON解析）看起来像这样的东西：

puts X

{"trends"=>[{"name"=>"blah blah", "query" =>"blah blah" and a bunch more info...
            {"name"=>"blah2 blah2", "query"=>"blah blah" and a bunch more...
            {"name"=>"blah3 blah3", and so on and so forth.}]}

我可以通过调用

来接近我想要的输出

X.each do |T|
  puts T["trends"]
end

我可以这样打印每一行：

{"name"=>"blah blah", "query" =>"blah blah" and a bunch more information
{"name"=>"blah2 blah2", "query"=>"blah blah" and a bunch more...
{"name"=>"blah3 blah3", and so on and so forth.}

如何让我的代码只打印趋势主题的名称？

我认为这将是一些事情

X.each do |T|
  puts T["trends"]["name"]
end

但这不起作用。如何才能显示

blah  blah
blah2 blah2
blah3 blah3

按照地区当我调用以下内容时，我从String转换为Integer错误。

X["trends"].each do |T|
    puts T["name"]
end

当我打电话给X.inspect时，我只是把我放在问题的顶部，并在趋势中添加了一组[]。

[{"trends"=>[{"name"=>"blah blah", "query" =>"blah blah" and a bunch more info...
            {"name"=>"blah2 blah2", "query"=>"blah blah" and a bunch more...
            {"name"=>"blah3 blah3", and so on and so forth.}]}]

我明白了。

X.each do |trend|
    trend["trends"].each do |topic|
        puts topic["name"]
    end
end

Answer 1

你必须迭代'trends'：

response = {"trends"=>[{"name"=>"blah blah", "query" =>"blah blah" and a bunch more information
            {"name"=>"blah2 blah2", "query"=>"blah blah" and a bunch more...
            {"name"=>"blah3 blah3", and so on and so forth.}]}

response['trends'].each do |trend|
  trend['name'] # do what you want with this
end

或者获取所有名称的数组：

response['trends'].map { |t| t['name'] }
# => ["blah blah", "blah2 blah2", "blah3 blah3"]

Twitter API实现＆＃34;趋势＆＃34;

1 个答案: