我得到了用python编写的以下函数。
def get_campaign_id(campaigns, campaign_name):
for c in campaigns:
if c['name'] == campaign_name:
return c['id']
return None
广告系列是一系列文字,例如:
campaigns = [{'name': 'campaign1', 'id': 91203}]
和campaign_name是str
答案 0 :(得分:1)
mapping =dict([c["name"],c["id"]) for c in campaigns]) #save this ... dont recreate it all the time
print mapping[campaign_name] # get the id by campaign name
可能是更好的方法......