我有JSON:
[
{
"Position": "ProjectManager",
"Salary": 2000
},
{
"Position": "BusinessAnalyst",
"Salary": 2001
},
{
"Position": "TechnicalLead",
"Salary": 2002
},
{
"Position": "SeniorSoftwareEngineer",
"Salary": 2003
},
{
"Position": "SoftwareEngineer",
"Salary": 2004
},
{
"Position": "JuniorSoftwareEngineer",
"Salary": 2005
},
{
"Position": "UIUXEngineer",
"Salary": 2006
},
{
"Position": "QALead",
"Salary": 2007
},
{
"Position": "SeniorQAEngineer",
"Salary": 2008
},
{
"Position": "QAEngineer",
"Salary": 2009
},
{
"Position": "JuniorQAEngineer",
"Salary": 2010
},
{
"Position": "SeniorAutomationEngineer",
"Salary": 2011
},
{
"Position": "AutomationEngineer",
"Salary": 2012
},
{
"Position": "JuniorAutomationEngineer",
"Salary": 2013
}
]
但我需要将它转换为这个例子:
{
"ProjectManager": "2000",
"BusinessAnalyst": "2001",
"TechnicalLead": "2002",
"SeniorSoftwareEngineer": "2003",
"SoftwareEngineer": "2004",
"JuniorSoftwareEngineer": "2005",
"UIUXEngineer": "2006",
"QALead": "2007",
"SeniorQAEngineer": "2008",
"QAEngineer": "2009",
"JuniorQAEngineer": "2010",
"SeniorAutomationEngineer": "2011",
"AutomationEngineer": "2012",
"JuniorAutomationEngineer": "2013"
}
正如你在第二个例子中所看到的,我只有值而没有属性。我怎样才能做到这一点? (Currentrly我的想法是将Json解析为字符串并删除所有匹配“Position:”或“Salary:”的标记)
答案 0 :(得分:2)
你不需要这么多东西。 我可以提到一种方法。
让你的json一个是probjson和结果asresjson
var arr=new [];
var res=new { arr }
for(var i in probjson.length){
var position=probjson[i].Position;
var salary=probjson[i].Salary;
var v = new { position=salary }
res.arr.add(V);
}
这不是一个完整的
试着想出一个主意。 thankz
答案 1 :(得分:0)
一种方法是迭代数组中的每个对象并填充字典:
// Using JSON.NET you can deserialize the JSON array as an enumerable
// of dynamically-typed objects (i.e. your array)
IEnumerable<dynamic> employees = JsonConvert
.DeserializeObject<IEnumerable<dynamic>>
(
jsonText
);
Dictionary<string, object> values = new Dictionary<string, object>();
foreach(dynamic employee in employees)
{
values.Add((string)employee.Position, (object)employee.Salary);
}
// .NET dictionaries are deserialized into JSON objects!
string convertedJson = JsonConvert.SerializeObject(values);
Check a working sample on .NET Fiddle!
如果你想要一个基于LINQ扩展方法的单行解决方案,那么:
string convertedJson = JsonConvert.SerializeObject
(
JsonConvert.DeserializeObject<IEnumerable<dynamic>>(jsonText)
.ToDictionary(employee => employee.Position, employee => employee.Salary)
);