如果这是一件简单的事情我很抱歉,我仍然是客观C的新手。 我有一个按钮,我试图改变每次按下它的图像和文本,但我的问题是,它一直在经历每一次,直到IBAction结束。 我需要做什么,每次点击按钮只做1“if”? 谢谢
-(IBAction)Button1:(UIButton *)sender {
if (button1TapCount == 0) {
button1TapCount = 1;
textString = (@"Button 1 Pressed");
button1ImageName = (@"test.png");
[self buttonschange];
}
if (button1TapCount == 1) {
button1TapCount = 2;
textString = (@"Button 1 Pressed twice");
button1ImageName = (@"test1.png");
[self buttonschange];
}
if (button1TapCount == 2) {
button1TapCount = 3;
textString = (@"Button 1 Pressed third time");
button1ImageName = (@"test2.png");
[self buttonschange];
}
}
答案 0 :(得分:1)
这是因为您没有使用else
并且您正在更改每个button1TapCount
语句中的if
,以便 next { {1}}将其解析为真。
使用:
if
答案 1 :(得分:0)
在第一个如果您将button1TapCount设置为1,那么第二个if也是如此。我认为你需要的是其他如果:
-(IBAction)Button1:(UIButton *)sender { if (button1TapCount == 0) { button1TapCount = 1; textString = (@"Button 1 Pressed"); button1ImageName = (@"test.png"); [self buttonschange]; } else if (button1TapCount == 1) { button1TapCount = 2; textString = (@"Button 1 Pressed twice"); button1ImageName = (@"test1.png"); [self buttonschange]; } else if (button1TapCount == 2) { button1TapCount = 3; textString = (@"Button 1 Pressed third time"); button1ImageName = (@"test2.png"); [self buttonschange]; } }
答案 2 :(得分:0)
使用 if-else 或返回或切换
-(IBAction)Button1:(UIButton *)sender {
if (button1TapCount == 0) {
button1TapCount = 1;
textString = (@"Button 1 Pressed");
button1ImageName = (@"test.png");
[self buttonschange];
return;
}
if (button1TapCount == 1) {
button1TapCount = 2;
textString = (@"Button 1 Pressed twice");
button1ImageName = (@"test1.png");
[self buttonschange];
return;
}
if (button1TapCount == 2) {
button1TapCount = 3;
textString = (@"Button 1 Pressed third time");
button1ImageName = (@"test2.png");
[self buttonschange];
return;
}
}