Question

我有一个这样的清单：

my_array= ["*","device",":","xyz"], ["+","asd","=","10","pdf","=","6"],
["+","dsa","=","1","pqa","=","2","dga","=","12"], ["*"]

我想做的是：

define('device','xyz')
define('asd','10')
define('pdf','6')
define('dsa','1')
define('pqa','2')
define('dga','12')

我接近的方式是：

i=0
while i < len(my_array):
    if my_array[i][0]=="*":
          print("'",my_array[i][1],"'","'",my_array[i][3:],"'")
    elif my_array[i][0]=="+":
          print("'",my_array[i][1],"'","'",my_array[i][3],"'")
          if my_array[i][4]=="\D":
              print("'",my_array[i][4],"'","'",my_array[i][6],"'")
          elif my_array[i][7]=="\D":
              print("'",my_array[i][7],"'","'",my_array[i][9],"'")
i=i+1

但是这样做，我得到索引错误。我知道问题出在哪里，但我不能用我非常糟糕的编程大脑来修复它。有人可以帮我吗？

Answer 1

首先回顾问题

if my_array[i][0]=="*":
      print("'",my_array[i][1],"'","'",my_array[i][3:],"'")

因为my_array中的最后一个元素是['*']而且它没有其他元素，并且您正在尝试访问my_array['*'][1]并且它给出索引错误。

您必须删除该元素或添加满足元素索引要求的成员。

Answer 2

对索引进行硬编码是一个肯定的迹象，表明你做错了 - my_array中的项目具有可变长度，因此你的一些索引不可避免地会失败。我想你想要的是：

for command in my_array:
    if command[0] in ("*", "+"):
        for start in range(1, len(command), 3):
            assignment = command[start:start+3]
            if assignment[1] in ("=", ":"):
                print assignment[0], assignment[2]

但值得注意的是，您似乎正在尝试编写文件解析器。虽然此代码解决了这个特定问题，但可能会改进您的整体方法。

Answer 3

假设您列表中的每个键都附加了一个值（例如，彼此之后没有两个星号），您可以进行一些简化：

我们将第一个值读作新dict的键，第二个值作为值。通过新整理的词典（d），您可以继续轻松工作，例如在for循环中：

array=["*","device",":","xyz"], ["+","asd","=","10","pdf","=","6"],
       ["+","dsa","=","1","pqa","=","2","dga","=","12"], ["*"]

d = {}

for list in array:
        new_key = None
        for item in list:
                if item in ['*',':','+','=']: continue
                if new_key == None:
                        new_key = item
                else:
                        d[new_key] = item
                        new_key = None


for key in d:
        define(key,d[key])

在列表内容上运行循环时出现索引错误

3 个答案: