方法不在laravel中工作

时间:2014-07-25 10:51:29

标签: php mysql laravel where

我试图在laravel中使用where语句,但作为回报,我得到一个空值。

这是代码

$vehicles_make_id = $_POST['vehicles_make_id']; //getting "Audi"    
$vehicles_name_trim = $_POST['vehicles_name_trim']; //getting "A3, 2.0T Premium Automatic"

$vehicles_name_trim_ar = explode(',', $vehicles_name_trim); 

$model_name = $vehicles_name_trim_ar[0]; //getting "A3"
$model_trim = $vehicles_name_trim_ar[1]; //getting "2.0T Premium Automatic"

$vehicles_body_ar = array_filter(array_unique(Model::where('model_make_id', $vehicles_make_id)
                                                   ->where('model_name',    $model_name)
                                                   ->where('model_trim',    $model_trim)
                                                   ->lists('model_body')));

print_r(2.0T Premium Automatic);

我检查了数据库中存在的值,但我得到一个空白数组

1 个答案:

答案 0 :(得分:1)

我认为你的错在哪里,不是他们错过了'='。

$vehicles_body_ar = array_filter(array_unique(Model::where('model_make_id', '=', $vehicles_make_id)->where('model_name', '=', $model_name)->where('model_trim', '=',  $model_trim)->lists('model_body')));

上次查询

$queries = DB::getQueryLog();
$last_query = end($queries);
print_r($last_query);