Question

我在PHP中有这个SQL查询：

$sql="SELECT * from customer c JOIN commsone_phonelines b where b.phone_number LIKE '%".$_POST["search"]."%' AND ";
    $sql.="c.company like '%".$_POST["search"]."%' OR ";
    $sql.="c.forename like '%".$_POST["search"]."%' OR ";
    $sql.="c.surname like '%".$_POST["search"]."%' OR ";
    $sql.="CONCAT_WS(' ',c.forename, c.surname) LIKE '%".$_POST["search"]."%' OR ";
    $sql.="c.phone like '%".$_POST["search"]."%' OR ";
    $sql.="c.accountnumber like '%".$_POST["search"]."%' OR ";
    $sql.="c.customerid like '%".$_POST["search"]."%' OR ";
    $sql.="c.voip_account like '%".$_POST["search"]."%' OR ";
    $sql.="REPLACE(c.postcode,' ','') LIKE '%".$_POST["search"]."%' OR ";
    $sql.="REPLACE(c.postcode,'',' ') LIKE '%".$_POST["search"]."%' OR ";
    $sql.="c.postcode LIKE '%".str_replace(' ','',$_POST["search"])."%' ";
    $sql.=" AND c.resellerid = '' ORDER BY company ASC";

基本上，我试图从两个不同的表中进行选择，我只需要从客户表中回显信息。

如果在commsone_phonelines表中找到了某些内容，则应该链接commsone_phonelines.customer_seq = customer.sequence

更新

我刚刚运行此查询：

SELECT c.* from customer c INNER JOIN commsone_phonelines b ON c.sequence = b.client_seq where b.phone_number LIKE '%boat%' OR c.company like '%boat%'

它返回customer表中的行是正确的，但是它显示了相同的行5次

Answer 1

就个人而言，我觉得这更容易阅读...

 $sql="
 SELECT c.* 
   FROM customer c 
   JOIN commsone_phonelines b 
     ON b.customer_seq = c.sequence
  WHERE b.phone_number                         LIKE '%{$_POST['search']}%' 
    AND ( c.company                            LIKE '%{$_POST['search']}%' 
       OR c.forename                           LIKE '%{$_POST['search']}%' 
       OR c.surname                            LIKE '%{$_POST['search']}%' 
       OR CONCAT_WS(' ',c.forename, c.surname) LIKE '%{$_POST['search']}%' 
       OR c.phone                              LIKE '%{$_POST['search']}%' 
       OR c.accountnumber                      LIKE '%{$_POST['search']}%' 
       OR c.customerid                         LIKE '%{$_POST['search']}%' 
       OR c.voip_account                       LIKE '%{$_POST['search']}%' 
       OR REPLACE(c.postcode,' ','')           LIKE '%{$_POST['search']}%'
        )
    AND c.resellerid = '' 
  ORDER 
     BY company ASC";

Answer 2

....我只需要从客户表中回复信息。

然后选择customer表的列。

$sql="SELECT c.* from customer c JOIN commsone_phonelines b where b.phone_number LIKE '%".$_POST["search"]."%' AND ";

其余查询保持不变。

修改

 $sql="SELECT DISTINCT c.col1,c.col2,c.col3 from customer c JOIN commsone_phonelines b where b.phone_number LIKE '%".$_POST["search"]."%' AND ";

SQL Query使用JOIN从两个表中进行选择

2 个答案: