Question

我正在为歌曲创建一个Google搜索应用。当用户输入歌曲名称时，AutotextView会建议您输入歌曲名称。对于每个单词更改，我必须调用AsycTask从web service获取数据并且它完全正常工作。我有两个问题。

它的响应很慢
当我用“Waka Waka”这样的空间调用歌曲时，AsyncTask不会设置适配器

我已经尝试过其他方式来解决它。我用%20替换空格，但空间适配器没有为AutotexView设置适配器listView

自动提交视频

textView.addTextChangedListener(new TextWatcher() {

        @Override
        public void onTextChanged(CharSequence cs, int arg1, int arg2,
                int arg3) {

            seq = cs;

        }

        @Override
        public void beforeTextChanged(CharSequence s, int arg1, int arg2,
                int arg3)
        {

        }

        @Override
        public void afterTextChanged(Editable arg0)
        {
            if(mAsync!=null) {
                mAsync.cancel(true);
            }
            //new SearchTask().execute(seq.toString().trim());
             mAsync =(SearchTask) new SearchTask().execute(seq.toString());
        }
    });

SearchTask

private class SearchTask extends AsyncTask<CharSequence, Void, String> 
    {
        ArrayAdapter<String> adapter;

        String[] array;

        @Override
        protected String doInBackground(CharSequence... params) 
        {
            try {
                HttpClient httpclient = new DefaultHttpClient();

                HttpPost httppost = new HttpPost(pak_url + params[0]);

                HttpResponse responce = httpclient.execute(httppost);

                HttpEntity httpEntity = responce.getEntity();

                String response = EntityUtils.toString(httpEntity);

                Log.d("response is", response);

                if (response != null) {
                    String substr = response.split("\\(")[2].split("\\)")[0];

                    array = substr.split(",");

                    for (int i = 0; i < array.length; i++) {

                        array[i] = array[i].replace("'", "");
                    }

                }

                return response;
            } catch (Exception e) {
                e.printStackTrace();
            }

            return null;
        }

        @Override
        protected void onPostExecute(String result) {
            super.onPostExecute(result);

            if (array != null) {
                adapter = new ArrayAdapter<String>(PlayListActivity.this,
                        android.R.layout.simple_list_item_1, array);

                textView.setAdapter(adapter);

                adapter.getFilter().filter(seq);
            } 
        }
    }

除AsyncTask之外，任何人都建议我使用快速方法。或者我可能在设置适配器或过滤时做错了什么。当我给出空格时，AsyncTask不会得到数据。

AsyncTask不会调用将空间应用于URL

0 个答案: