Question

如何获得子组的计数。我有Table1和Table2（下面）。如何获取表格结果。我累了分组，但只设法获得总行数。我在Microsoft SQL中尝试它。

Table1
ID  PriID   Function
1   500     A
2   500     B
3   500     C
4   501     A
5   501     B
6   502     C
7   503     A


Table2
PriID   Color
500     Green
501     Red
502     Green
503     Green


Result
Function    Green       Red     Total
A           2           1       3
B           1           1       2
C           2           0       2

下面是我尝试的当前

SELECT t1.Function, Count(t1.PriID) as Total FROM Table1 t1 
LEFT JOIN Table2 t2 on t1.PriID = t2.PriID
GROUP BY t1.function

我得到了这个

Result
Function    Total
A           3
B           2
C           2

Answer 1

试试这个

SELECT t1.Function, 
SUM(CASE WHEN Color = 'Green' THEN 1 ELSE 0 END) AS Green, 
SUM(CASE WHEN Color = 'Red' THEN 1 ELSE 0 END) AS Red, 
Count(t1.PriID) as Total FROM Table1 t1 
LEFT JOIN Table2 t2 on t1.PriID = t2.PriID
GROUP BY t1.function

Answer 2

这是做这些事情的最佳方法

;with cte as
(
select [Function],t1.priID,color
     from tbl1 t1 
        join tbl2 t2 on t1.priID = t2.priid
),def as
(
    select [Function],[Green],[Red] 
    from 
    (
        select [Function],color,priID  from cte) dk
        Pivot (count(priID) for color in([Green],[Red] )
     ) pvt 
) select *,green+red [Total] from def

Answer 3

select [function], ISNULL(Green, 0) Green, ISNULL(Red, 0) Red,
       ISNULL(Green, 0) + ISNULL(Red, 0) Total 
from 
    (
        select *, count([function]) 'X' from 
        (
            select t2.color, t1.[function]  from table1 t1 
            JOIN table2 t2 on t1.prid = t2.prid 
        )A 
        group by color, [function] 
    )B pivot (max(X) for color IN ([Green],[Red]))as d

Answer 4

试试这个：

;with cte as
(select [function], 
 Sum(CASE WHEN t1.PriId <> 501 Then 1 Else 0 END) over(partition by [function] order by t1.priid) Green,
 Sum(CASE WHEN t1.PriId = 501 Then 1 Else 0 END) over(partition by [function] order by t1.priid) Red,
 Count(*) over (partition by [function] order by t1.priid) Total,
 Row_Number() over (partition by [function] order by t1.priid desc) rn
 from
 table1 t1 
 left join table2 t2 on t1.priid = t2.priid)

select [function],green,red,total
from cte
where rn = 1

此查询使用窗口函数（从SQL Server 2005开始提供），这消除了对GROUP BY子句的需要

Demo

Answer 5

您好应该使用PIVOT来获得结果。像这样：

CREATE TABLE #table（id int，priID int，[FUNCTION] varchar（5））

INSERT INTO #table ( id,priID,[FUNCTION] )
VALUES  (  1, 500,'a' ), (  2, 500,'b' ), (  3, 500,'c' ), (  4, 501,'a' ), (  5, 501,'b' ), (  6, 502,'c' )


CREATE TABLE #table2 (priID int, color varchar(20))

INSERT INTO #table2 (priID,color )
VALUES  (  500,'green' ), (  501, 'red' ), (  502,'yellow' )


SELECT t.[FUNCTION], t2.color, COUNT(t.priID) AS cnt 
INTO #result
FROM #table AS T
INNER JOIN #table2 AS T2 ON T2.priID = T.priID
GROUP BY t.[FUNCTION], t2.color


SELECT [FUNCTION], green, red, yellow
FROM (  SELECT [FUNCTION], color, cnt
        FROM #result AS R) AS p
PIVOT ( MAX(cnt) FOR color IN (green, red, yellow)) AS pvt

http://rextester.com/ROPBBS57014

Answer 6

表格中所有记录的最佳方式（如果您编辑，删除或插入新记录）是：

 

    With  t (F,PriID,Color) as 
    (
    SELECT     Table1.F, Table2.PriID, Table2.Color
    FROM         Table1 INNER JOIN
                          Table2 ON Table1.PriID = Table2.PriID
    GROUP BY Table2.PriID,F,Color) 
    select F,Color,COUNT(F)  as total from t group by F,Color

你明白了：

结果

Function    Color   total
A           Green   2
B           Green   1
C           Green   2
A           Red     1
B           Red     1

如何在SQL中获取子组的Count

6 个答案: