Question

我已经开始做一个小的swift / spritekit项目来教我自己的游戏开发。它以等距地图开始，我设法绘制。但是我在地图的不同瓷砖上获得精确的触摸位置时遇到了麻烦。它有效，但有点不合适，似乎不一致。

以下是我的功能：

class PlayScene: SKScene {

let map = SKNode()
    override func didMoveToView(view: SKView) {

        let origin = view.frame.origin
        let mapOrigin = CGPointMake(origin.x + self.frame.width / 4, origin.y - self.frame.height / 4)


        let mapConfig: Int[][] =

       [[0, 0, 0, 0, 1, 0, 0, 0],
        [0, 0, 0, 0, 1, 0, 0, 0],
        [0, 0, 0, 0, 1, 0, 0, 0],
        [2, 2, 2, 2, 1, 2, 2, 2],
        [0, 0, 0, 0, 1, 0, 0, 0],
        [0, 0, 0, 0, 1, 0, 0, 0],
        [0, 0, 0, 0, 1, 0, 0, 0],
        [0, 0, 0, 0, 1, 0, 0, 0]]

    drawMap(mapConfig, mapOrigin: mapOrigin)
}

使用：

 func drawMap(mapConfig:Int[][], mapOrigin:CGPoint)
{
    let tileHeight:CGFloat = 25.5
    let numColumns:Int = 8
    let numRows:Int = 8

    var position = mapOrigin
    var column: Int = 0
    var row: Int = 0

    for column = 0; column < numColumns; column++
    {
        for row = 0; row < numRows; row++
        {
            position.x = mapOrigin.x + CGFloat(column) * tileHeight
            position.y = mapOrigin.y + CGFloat(row) * tileHeight
            let isoPosition = twoDToIso(position)
            placeTile(isoPosition, mapConfig: mapConfig[row][column])
        }
    }
    self.addChild(map)
}

func placeTile(position:CGPoint, mapConfig:Int)
{
 switch mapConfig
    {
    case 0:
        let sprite = SKSpriteNode(imageNamed:"grassTile")
        sprite.position = position
        sprite.setScale(0.1)
        sprite.name = "\(position)"
        self.map.addChild(sprite)
    case 1:
        let sprite = SKSpriteNode(imageNamed:"roadTile")
        sprite.position = position
        sprite.setScale(0.1)
        sprite.name = "\(position)"
        self.map.addChild(sprite)
    default:
        let sprite = SKSpriteNode(imageNamed:"roadTileLTR")
        sprite.position = position
        sprite.setScale(0.1)
        sprite.name = "\(position)"
        self.map.addChild(sprite)
    }
}

然后我想隐藏我触摸的瓷砖（用于测试）：

override func touchesBegan(touches: NSSet, withEvent event: UIEvent)
{
    for touch: AnyObject in touches
    {
        let locationNode = touch.locationInNode(self)
        nodeAtPoint(locationNode).hidden = true
    }
}

但它并不总是隐藏正确的瓷砖。那我该怎么解决呢？我的代码是否根本错误（可能）？或者我需要以某种方式将位置转换为iso坐标？或者使用瓷砖位掩码？

感谢您的帮助，无论如何！

Answer 1

我在等轴测图中遇到了类似的问题。

问题是您单击的节点大于显示的节点（它具有透明部分）。有关此问题的更好解释，请参阅my question here。

以下是我如何解决它（抱歉代码在Objective-C中）：

1.在tile的边缘之后创建一个CGPathRef（tileSize是纹理的大小）。此代码适用于常规等距切片，而不是六边形，但想法是一样的。

// ObjC
-(CGPathRef)createTextureFrame:(CGSize)tileSize
{
    CGMutablePathRef path = CGPathCreateMutable();
    CGPathMoveToPoint(path, NULL, 0, -(self.tileSize.height / 2));
    CGPathAddLineToPoint(path, NULL, (self.tileSize.width / 2), 0);
    CGPathAddLineToPoint(path, NULL, 0, (self.tileSize.height / 2));
    CGPathAddLineToPoint(path, NULL, -(self.tileSize.width / 2), 0);
    CGPathCloseSubpath(path);
    return path;
}

// Swift
func createTextureFrame(tileSize:CGSize) -> CGPathRef {
    CGMutablePathRef path = CGPathCreateMutable()
    CGPathMoveToPoint(path, nil, 0, -(self.tileSize.height / 2))
    CGPathAddLineToPoint(path, nil, (self.tileSize.width / 2), 0)
    CGPathAddLineToPoint(path, nil, 0, (self.tileSize.height / 2))
    CGPathAddLineToPoint(path, nil, -(self.tileSize.width / 2), 0)
    CGPathCloseSubpath(path)
    return path
}

2.创建一个函数，检查给定的点是否在CGPathRef（textureFrame）中。

// ObjC
-(BOOL)isPointOnNode:(CGPoint)point
{
    return CGPathContainsPoint(textureFrame, NULL, point, YES);
}

// Swift
func isPointOnNode(point:CGPoint) -> Bool {
    return CGPathContainsPoint(textureFrame, nil, point, YES)
}

3.对于每个触摸的节点，检查我们所在的textureFrame。

// ObjC
UITouch *touch = [touches anyObject];
NSArray *nodes = [self nodesAtPoint:[touch locationInNode:self]];
for (SKNode *node in nodes)
{
    CGPoint locationInNode = [touch locationInNode:node];
    if ([node isPointOnNode:locationInNode])
    {
        node.hidden = YES;
    }
}

// Swift
var touch = touches.anyObject() as UITouch
var nodes = self.nodesAtPoint(touch.locationInNode(self))
for node in nodes as [SKNode] {
    var locationInNode = touch.locationInNode(node)

    if node.isPointOnNode() {
        node.hidden = true
    }
}

我不知道这是否是最佳解决方案，但效果很好。我希望它有所帮助：）

编辑：添加了Swift版本的代码

Swift Spritekit等距地图触摸位置

1 个答案: