Question

我试图从屏幕上复制PictureBox的位置。我的代码如下所示：

Form1.cs中：

_recorder = new ScreenRecord();
_recorder.StartRecording(
   pictureBox1,
   pictureBox1.RectangleToScreen(new Rectangle())
);

ScreenRecord.cs：

class ScreenRecord
{
   private ScreenBitmap scBitmap;

   public void StartRecording(PictureBox cam, Rectangle rect)
   {
      scBitmap = new ScreenBitmap(cam, rect);
      cam.Image = scBitmap.GetBitmap();
   }
}

ScreenBitmap.cs：

class ScreenBitmap
{
   private PictureBox camBox;
   private Rectangle camLocation;

   public ScreenBitmap(PictureBox cam, Rectangle rect)
   {
      camBox = cam;
      camLocation = rect;
   }

   public Bitmap GetBitmap()
   {
      Bitmap screenBitmap = GetScreen();
      return screenBitmap;
   }

   private Bitmap GetScreen()
   {
      Bitmap scBitmap = new Bitmap(camBox.Width, camBox.Height);
      Graphics g = Graphics.FromImage(scBitmap);

      g.CopyFromScreen(
         camLocation.X,
         camLocation.Y,
         0,
         0,
         new Size(camBox.Width, camBox.Height)
      );

      return scBitmap;
   }
}

我正在获取pictureBox1矩形，然后从屏幕上复制，但看起来它不起作用。如果我尝试以下代码：

g.CopyFromScreen(
   camLocation.X,
   121,
   0,
   0,
   new Size(camBox.Width, camBox.Height)
);

其中121是一个随机数它工作（我得到一个图像，而不是我想要的部分，但它有效）所以矩形的Y坐标可能是错误的？或者我错过了一些东西......

Answer 1

这将通过不透明技巧为您提供PictureBox背后的内容。其余的你可以很容易地转移到你的代码：

 //just when you are about to capture screen take opacity and later restore it.
 this.Opacity = 0.0;
 Point first = PointToScreen(pictureBox1.Location);

 Bitmap bit = new Bitmap(pictureBox1.Width, pictureBox1.Height);
 Graphics g = Graphics.FromImage(bit);

 g.CopyFromScreen(first.X,first.Y, 0, 0, pictureBox1.Size);
 this.Opacity = 1.0;
 pictureBox1.Image = bit;

您可以通过创建新的WinForms项目，添加Button和PictureBox来测试此代码，并将此代码放入Button＆＃39; s {{1}事件处理程序。

元素矩形

1 个答案: