Question

在Wordpress的SQL语句上遇到一些问题。创建了一个自定义字段＆＃34; member_name＆＃34;在key = member_name下的order3中保存。我需要创建一个报告，显示每个member_name的数量的和（在key =＆＃34; _qty＆＃34;下保存的order2）。

TABLES：

order1 - order1_id, order3_id 
order2 - order2_id, key, value
order3 - order3_id, key, value

示例：

order1 
order1_id - order3_id 
2 - 292
3 - 292
4 - 281

order2 
order2_id - key - value 
2 - '_qty' - 1
3 - '_qty' - 2
4 - '_qty' - 1

order3 
order3_id - key - value 
292 - 'member_name' - John 
292 - 'member_name' - John 
281 - 'member_name' - Bill

期望的结果：

John 3
Bill 2

以下是我正在使用的内容：

SELECT order3.value, a.member_count 
FROM ((order3
INNER JOIN order3(select value, sum(*) as member_count
  FROM order2
  GROUP BY value
  WHERE order2.value='_qty') a
ON order3.order3_id=order1.order1_id)
INNER JOIN order2
ON order2.order2_id=order1.order1_id)
GROUP BY a.member_count
WHERE order3.key="member_name";

Answer 1

尝试以下查询。它首先获得每个qty的总order3_id值。然后，从order3表中查找名称。

SELECT DISTINCT
    o3.value,
    totals.total_qty
FROM order3 o3
INNER JOIN
(
    SELECT
        o1.order3_id order3_id,
        sum(o2.value) total_qty
    FROM order2 o2
    INNER JOIN order1 o1 ON o2.order2_id = o1.order1_id AND o2.key = '_qty'
    GROUP BY o1.order3_id
) totals
ON o3.order3_id = totals.order3_id AND o3.key = 'member_name';

您可以在order3表中按名称分组。但是，如果2 order3_id具有相同的名称，您将得到意外的结果。

会员数量总和

1 个答案: