我有这个数据：
Pclass Name Sex Age Fare family
56 1 Mr male NA 35.5000 0
2 1 Mrs female 38.00 71.2833 1
3 3 Miss female 26.00 7.9250 0
890 1 Mr male 26.00 30.0000 0
861 3 Mr male 41.00 14.1083 2
864 3 Miss female NA 69.5500 10
862 2 Mr male 21.00 11.5000 1
我想在此条件下替换年龄NA值：
If Name== Mr & Pcalss==1 Then Age=41
我该怎么做？
答案 0 :(得分：1)
dat <- structure(list(Pclass = c(1L, 1L, 3L, 1L, 3L, 3L, 2L), Name = c("Mr",
"Mrs", "Miss", "Mr", "Mr", "Miss", "Mr"), Sex = c("male", "female",
"female", "male", "male", "female", "male"), Age = c(NA, 38,
26, 26, 41, NA, 21), Fare = c(35.5, 71.2833, 7.925, 30, 14.1083,
69.55, 11.5), family = c(0L, 1L, 0L, 0L, 2L, 10L, 1L)), .Names = c("Pclass",
"Name", "Sex", "Age", "Fare", "family"), class = "data.frame", row.names = c("56",
"2", "3", "890", "861", "864", "862"))
dat$Age[with(dat, Name=="Mr" & Pclass==1 & is.na(Age))] <- 41
dat
# Pclass Name Sex Age Fare family
#56 1 Mr male 41 35.5000 0 ##NA in Age got replaced by 41
#2 1 Mrs female 38 71.2833 1
#3 3 Miss female 26 7.9250 0
#890 1 Mr male 26 30.0000 0
#861 3 Mr male 41 14.1083 2
#864 3 Miss female NA 69.5500 10
#862 2 Mr male 21 11.5000 1
假设您的数据集是：
dat <- structure(list(Pclass = c(1L, 1L, 3L, 1L, 3L, 3L, 2L), Name = structure(c(2L,
4L, 1L, 2L, 3L, 1L, 2L), .Label = c("Miss", " Mr", " Mr ",
"Mrs"), class = "factor"), Sex = structure(c(2L, 1L, 1L, 2L,
2L, 1L, 2L), .Label = c("female", "male"), class = "factor"),
Age = c(NA, 38, 26, 26, 41, NA, 21), Fare = c(35.5, 71.2833,
7.925, 30, 14.1083, 69.55, 11.5), family = c(0L, 1L, 0L,
0L, 2L, 10L, 1L)), .Names = c("Pclass", "Name", "Sex", "Age",
"Fare", "family"), class = "data.frame", row.names = c("56",
"2", "3", "890", "861", "864", "862"))
dat$Age[with(dat, Name=="Mr" & Pclass==1 & is.na(Age))] <- 41 #will not work
levels(dat$Name)
[1] "Miss" " Mr" " Mr " "Mrs"
library(stringr)
dat$Name <- str_trim(dat$Name)
dat$Age[with(dat, Name=="Mr" & Pclass==1 & is.na(Age))] <- 41
head(dat,1)
# Pclass Name Sex Age Fare family
#56 1 Mr male 41 35.5 0