Question

SELECT * from (
SELECT 'Rupesh' Name ,'2014-02-27 00:00:00.000' OfficeDate,'9.30' InTime,'' OutTime
UNION
SELECT 'Rupesh' Name,'2014-02-27 00:00:00.000' OfficeDate,'' InTime,'6.30' OutTime
UNION
SELECT 'Rupesh' Name ,'2014-02-26 00:00:00.000' OfficeDate,'11.30' InTime,'' OutTime
UNION
SELECT 'Rupesh' Name ,'2014-02-26 00:00:00.000' OfficeDate,'' InTime,'9.30' OutTime
)p

采样数据：

----------------------------------------------------
Name    |OfficeDate                 |InTime|OutTime
----------------------------------------------------
Rupesh  |   2014-02-26 00:00:00.000 |       |9.30
Rupesh  |   2014-02-26 00:00:00.000 |11.30  |   
Rupesh  |   2014-02-27 00:00:00.000 |       |6.30
Rupesh  |   2014-02-27 00:00:00.000 |9.30   |   
----------------------------------------------------

我想要的结果是以下方式：

Rupesh  2014-02-26 00:00:00.000 11.30   9.30    

Rupesh  2014-02-27 00:00:00.000 9.30    6.30

Answer 1

您希望按Name，OfficeDate分组并合并InTime和OutTime？您可以使用以下使用ranking functions的CTE：

WITH CTE AS(
  SELECT Name, OfficeDate, 
         InTimeOld = InTime, OutTimeOld = OutTime,
         InTimeNew = MAX(InTime) OVER(PARTITION BY Name, OfficeDate), 
         OutTimeNew= MAX(OutTime)OVER(PARTITION BY Name, OfficeDate),
         RN = Row_Number() Over (Partition By Name, OfficeDate
                                 Order By Name, OfficeDate, Intime, OutTime)
  FROM dbo.TableName t
)
SELECT Name, OfficeDate, InTime = InTimeNew, OutTime = OutTimeNew
FROM CTE
WHERE RN = 1

Sql-Fiddle

Answer 2

你可以这样做：

SELECT 
    TABLE1.Name,
    TABLE1.OfficeDate,
    MAX(TABLE1.InTime) AS InTime,
    MAX(TABLE1.OutTime) AS OutTime
FROM TABLE1
GROUP BY
    TABLE1.Name,
    TABLE1.OfficeDate

Answer 3

谢谢你guyz，但我在这里解决了它的解决方案：

SELECT name, OfficeDate, [InTime] ,[OutTime] from 
 (
    SELECT name,OfficeDate, 'OutTime' status,OutTime Times from #DATA           
    UNION           
    SELECT name,OfficeDate, 'InTime' status, InTime Times from #DATA    
 ) x
pivot 
(
   MAX(Times)
   for status in (InTime,OutTime)
) p

Answer 4

参考Fiddle：

SELECT 
    TABLE1.Name,
    TABLE1.OfficeDate,
    MIN(TABLE1.InTime) AS InTime,   -- Minimum Intime
    MAX(TABLE1.OutTime) AS OutTime   --- Maximum Outtime
FROM TableName TABLE1
GROUP BY
    TABLE1.Name,
    TABLE1.OfficeDate;

如何在一行中获取同名的多行数据？

4 个答案: