Question

我有一个考勤表名称出席，可能问题是如何获得student_no，其中时间等于早晨（0:00 - >晚上11:59）或下午等于（12:00 - ＆gt; ;晚上11:59）

CREATE TABLE IF NOT EXISTS `attendance` (
`ATTENDANCE_NO` int(10) NOT NULL AUTO_INCREMENT,
`A_DATE` date NOT NULL,
`TIME` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`JOB_SERVICE` varchar(255) NOT NULL,
`ATTENDER_NO` int(10) NOT NULL,
`STUDENT_NO` varchar(20) NOT NULL,
`ATTENDANCELAT` varchar(255) NOT NULL,
`ATTENDANCELONG` varchar(255) NOT NULL,
PRIMARY KEY (`ATTENDANCE_NO`),
KEY `STUDENT_NO` (`STUDENT_NO`),
KEY `ATTENDER_NO` (`ATTENDER_NO`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=6 ;

--
-- Dumping data for table `attendance`
--

INSERT INTO `attendance` (`ATTENDANCE_NO`, `A_DATE`, `TIME`, `JOB_SERVICE`,       `ATTENDER_NO`, `STUDENT_NO`, `ATTENDANCELAT`, `ATTENDANCELONG`) VALUES
(2, '2014-07-24', '2014-07-24 01:00:00', 'PICKUP', 3, 'S123456789', '13.624004',   '123.194269'),
(3, '2014-07-24', '2014-07-23 18:25:13', 'DROPOFF', 3, 'S123456789', '13.6295657',  '123.184346'),
(4, '2014-07-24', '2014-07-23 17:28:09', 'PICKUP', 3, 'S234567890', '13.625985', '123.191780'),
(5, '2014-07-24', '2014-07-23 18:27:28', 'DROPOFF', 3, 'S234567890', '13.6295657', '123.184346');

任何帮助将不胜感激。提前谢谢。

Answer 1

试试这个。我希望这会对你有所帮助。

select * from attendance;

#morning time
select * from attendance where 
HOUR(`TIME`) < 12;

#after noon time

select * from attendance where 
HOUR(`TIME`) >= 12;

SQLFiddle链接：http://sqlfiddle.com/#!2/2a41da/7

还引用日期的所有mysql函数：http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html

在特定时间获取数据

1 个答案: