如何使用php获取文本文件中的某些字符串

Question

我想在文本中回显/获取某些字符串，如： 该文件是test.txt 文件内容字符串是＆＃34;数据。我＆＃39; d。 1。在＆＃34; 如何回显/只获取没有＆＃39; 1＆＃39;或者＆＃39;我＆＃39; d＆＃39;不是其他字符串...... 请帮帮我

Answer 1

试试这个..

<?php
$data = file_get_contents("input.txt"); //read the file
$convert = explode("\n", $data); //create array separate by new line

for ($i=0;$i<count($convert);$i++)  
{
echo $convert[$i].', '; //write value by index
}
?>

---

输出：

数据，我，1，in，

或者如果它是某个字符串..

<?php
$data = file_get_contents("input.txt"); //read the file
$convert = explode("\n", $data); //create array separate by new line

for ($i=0;$i<count($convert);$i++)  
{
echo $convert[$i]=='1'. ; //write value by index
}
?>

---

输出：

1

Answer 2

<?php

$file= file_get_contents("test.txt"); 
$convert = explode("\n", $file); `

for ($i=0;$i<count($convert);$i++)  
{

    if($i<count-1)///make your you doesn't have , in your last line
    {

        echo $convert[$i].', '; //it is writing the value`
    }
    else
    {

        echo $convert[$i];`

    }

}
?>

Answer 3

$string = " data . I'd . 1 .in ";
// remove the spaces
$string = str_replace(' ', '',$string);
// convert to array
$words = explode('.', $string);

print $words[1]; // I'd
print $words[2]; // 1