我有以下表格:
Pools Members User
----------------------------------------------------------------------------------
id name id pool_id user_id id name
----------------------------------------------------------------------------------
1 abc 1 1 101 101 test1
2 xyz 2 1 102 102 test2
3 2 105 105 test5
4 2 106 106 test6
当用户登录时,他应该查看他不是其成员的那些池的列表,例如,如果id为101的用户登录,则应显示以下结果。
Pool Members
xyz 2 members
答案 0 :(得分:2)
你可能想要这个
SELECT name AS Pool,
count(pool_id) AS Members
FROM Pools
JOIN Members ON Pools.id=Members.pool_id
WHERE Pool.id NOT IN
(SELECT pool_id
FROM Members
WHERE user_id=101)
GROUP BY Member.pool_id