Question

我正在研究一个计算器程序，要求用户输入执行程序的问题是我只希望程序循环的次数与输入的值一样多。不幸的是，程序只是继续循环。如何修复它以便它只在用户输入时运行x次？

 loop=1
choice=0  
while loop == 1:
    print("Welcome to Calculator Function!")
    n =input("How many operations do you want to do?: ")
    for n in xrange(6):
                print("Your options are:")
                print(" ")
                print("1) Addition")
                print("2) Subtraction") 
                print("3) Multiplication")
                print("4) Division")
                print("5) Quit CalculatorFunction.py")
                print(" ")

                choice = input("Choose your option: ")
                if choice == 1:
                    add1 = input("Add what: ")
                    add2 = input("To what: ")
                    print add1, "+", add2, "=", add1+add2
                elif choice == 2:
                    sub2 = input("Subtract what: ")
                    sub1 = input("From what: ")
                    print sub1, "-", sub2, "=", sub1-sub2
                elif choice == 3:
                    mult1 = input("Multiply what: ")
                    mult2 = input("To what: ")
                    print mult1, "*", mult2, "=", mult1*mult2
                elif choice == 4:
                    div2= input("Divide what: ")
                    div1= input("From what: ")
                    print div1, "/", div2, "=", div1/div2
                elif choice == 5:
                    loop = 0
                    print"Thank you for using CalculatorFunction.py have a good day!" 
                else:
                    print"No selection made, please try again."
    return[n() for n in xrange(6)]

Answer 1

你需要在n范围内循环并在该循环之外突破

choice = 0
while True: # while True will keep going until we break
    print("Welcome to Calculator Function!")
    n = input("How many operations do you want to do?: ")
    for _ in xrange(n): # how many times user want to use the calc
            print("Your options are:")
            print(" ")
            print("1) Addition")
            print("2) Subtraction")
            print("3) Multiplication")
            print("4) Division")
            print("5) Quit CalculatorFunction.py")
            print(" ")

            choice = input("Choose your option: ")
            if choice == 1:
                add1 = input("Add what: ")
                add2 = input("To what: ")
                print add1, "+", add2, "=", add1+add2
            elif choice == 2:
                sub2 = input("Subtract what: ")
                sub1 = input("From what: ")
                print sub1, "-", sub2, "=", sub1-sub2
            elif choice == 3:
                mult1 = input("Multiply what: ")
                mult2 = input("To what: ")
                print mult1, "*", mult2, "=", mult1*mult2
            elif choice == 4:
                div2= input("Divide what: ")
                div1= input("From what: ")
                print div1, "/", div2, "=", div1/div2
            elif choice == 5:
                loop = 0
                print"Thank you for using CalculatorFunction.py have a good day!"
            else:
                print"No selection made, please try again."
    break # end after "n" loops

或者只是在没有while的情况下循环输入n的范围：

loop=1
choice=0

print("Welcome to Calculator Function!")
n = input("How many operations do you want to do?: ")
for _ in xrange(n):
        print("Your options are:")
        print(" ")
        print("1) Addition")
        print("2) Subtraction")
        print("3) Multiplication")
        print("4) Division")
        print("5) Quit CalculatorFunction.py")
        print(" ")

创建一个在X Amount次之后终止的程序

1 个答案: