我试图找出为什么我无法从两个edittexts获取有效字符串
以下几行是我所说的
String newPin = etNewPassword.getText().toString();
String conPin = etConfirmPassword.getText().toString();
以下是整个文件
public class PasswordDialogPreference extends DialogPreference {
TextView tvOldPassword;
TextView tvNewPassword;
TextView tvConfirmPassword;
EditText etOldPassword;
EditText etNewPassword;
EditText etConfirmPassword;
SharedPreferences sharedPrefs;
SharedPreferences.Editor editor;
public PasswordDialogPreference(Context context, AttributeSet attrs) {
super(context, attrs);
setDialogLayoutResource(R.layout.password_dialog_preference);
setPositiveButtonText(android.R.string.ok);
setNegativeButtonText(android.R.string.cancel);
setDialogIcon(null);
setPersistent(false);
}
@Override
public void onBindDialogView(View view) {
tvOldPassword = (TextView) view.findViewById(R.id.tvOldPassword);
tvNewPassword = (TextView) view.findViewById(R.id.tvNewPassword);
tvConfirmPassword = (TextView) view.findViewById(R.id.tvConfirmPassword);
etOldPassword = (EditText) view.findViewById(R.id.etOldPassword);
etNewPassword = (EditText) view.findViewById(R.id.etOldPassword);
etConfirmPassword = (EditText) view.findViewById(R.id.etOldPassword);
sharedPrefs = PreferenceManager
.getDefaultSharedPreferences(getContext());
if (sharedPrefs.getString("prefPasscode", "").length() < 4) {
tvOldPassword.setVisibility(View.GONE);
etOldPassword.setVisibility(View.GONE);
}
super.onBindDialogView(view);
}
@Override
protected void onDialogClosed(boolean positiveResult) {
super.onDialogClosed(positiveResult);
persistBoolean(positiveResult);
}
@Override
protected void onPrepareDialogBuilder(AlertDialog.Builder builder) {
super.onPrepareDialogBuilder(builder);
//builder.setNegativeButton(null, null);
builder.setPositiveButton(android.R.string.ok, new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
sharedPrefs = PreferenceManager
.getDefaultSharedPreferences(getContext());
String oldPin;
String newPin = etNewPassword.getText().toString();
String conPin = etConfirmPassword.getText().toString();
Log.d("pins", etNewPassword.getText().toString() + " " + etConfirmPassword.getText().toString());
if (newPin.equals(conPin)) {
//editor.putString("prefPasscode", etConfirmPassword.getText().toString());
//editor.commit();
Toast.makeText(getContext(), "Pin saved." + conPin,
Toast.LENGTH_SHORT
).show();
} else if (etNewPassword.getText().toString().length() != 4) {
Toast.makeText(getContext(), "Pin must be 4 digits.",
Toast.LENGTH_SHORT
).show();
} else if (!etNewPassword.getText().toString().equals(etConfirmPassword.getText().toString())) {
Toast.makeText(getContext(), "Pin does not match.",
Toast.LENGTH_SHORT
).show();
}
}
});
}
}
以下是edittext布局,我不确定inputtype:numberpassword是否导致任何问题
<EditText
android:id="@+id/etNewPassword"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:textSize="15dp"
android:maxLength="4"
android:inputType="numberPassword"
android:width="100dp"
android:key="keyNewPasscode"/>
<EditText
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:id="@+id/etConfirmPassword"
android:maxLength="4"
android:textSize="15dp"
android:inputType="numberPassword"
android:width="100dp"
android:key="keyConfirmPasscode"/>
答案 0 :(得分:1)
您有类似的观点ID:
etOldPassword = (EditText) view.findViewById(R.id.etOldPassword);
etNewPassword = (EditText) view.findViewById(R.id.etOldPassword);
etConfirmPassword = (EditText) view.findViewById(R.id.etOldPassword);