更新命令输出

Question

我想在记录不存在时写一个更新命令。发消息后

    mysqli_query($connection,"UPDATE system SET count  ='1'   where  code ='929'");

我的意思是，如果有一个929代码的记录字段更新信息，否则给出消息

Answer 1

试试这个：

$num_modified = mysqli_query($connection,"UPDATE system SET count  ='1'   where  code ='929'");
if ($num_modified != 1) { 
 echo "Failed to modify!";
}