Question

我正在进行以下查询

SELECT auth_number,
  status
FROM auth_services_cnv auth
WHERE EXISTS
  (SELECT 1
  FROM
    (SELECT COUNT(*) b
    FROM auth_services_cnv
    WHERE status   ='D'
    AND auth_number=auth.auth_number
    GROUP BY auth_number
    ) a1 ,
    (SELECT COUNT(*) c
    FROM auth_services_cnv
    WHERE 1        =1
    AND auth_number=auth.auth_number
    GROUP BY auth_number
    ) a2
  WHERE a1.b=a2.c
  );

/

我收到以下错误

ORA-00904：＆＃34; AUTH＆＃34;。＆＃34; AUTH_NUMBER＆＃34;：无效的标识符 00904. 00000 - ＆＃34;％s：无效标识符＆＃34; *原因：
*行动：行错误：42列：21

其实我的要求是这样的

auth_number状态 1个D 1 P 1个D 1个D 2 D. 2 D. 2 D

我需要选择auth_number，其状态为全部＆＃39; D＆＃39;。这意味着我需要选择带有2的auth_number。

请帮帮我。提前谢谢。

- 桑德亚

Answer 1

您可以改用：

SELECT  auth_number,
        status
FROM auth_services_cnv
WHERE auth_number NOT IN (SELECT auth_number
                          FROM auth_services_cnv
                          WHERE Status <> 'D')

Answer 2

这是一个只有oracle的解决方案

SELECT auth_number
FROM auth_services_cnv 
MINUS
SELECT auth_number
FROM auth_services_cnv 
WHERE Status <> 'D'

子查询中的标识符无效

2 个答案: